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Studentka2010 [4]
3 years ago
5

How does temperature affect magnetism

Chemistry
1 answer:
erastovalidia [21]3 years ago
3 0
Temperature affects magnetism by either strengthening or weakening a magnet's attractive force. A magnet subjected to heat experiences a reduction in its magnetic field as the particles within the magnet are moving at an increasingly faster and more sporadic rate.
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A 1-liter bag of iv solution would contain how many cubic centimeters of fluid?
weeeeeb [17]
A 1-liter bag of IV solution would contain how many cubic centimeters of fluid?

1000 cc
8 0
3 years ago
Which of the following is NOT a characteristic of minerals
o-na [289]

Answer:

A. Occur in gaseous and liquid state

Explanation:

The choice that is not a characteristic of minerals is that minerals occur in gaseous and liquid state.

All minerals are solid inorganic compounds.

  • A mineral is an inorganic compound that is formed naturally.
  • They have a definite and specific chemical composition.
  • Minerals are the building blocks of rocks.
  • When minerals aggregates together, they form different rock types.
  • There is no known mineral that is in fluid state.
  • All minerals are solids.
  • Examples are quartz, kaolinite, gypsum e.t.c
6 0
3 years ago
If a 600 gram radioactive sample goes through 3 half-lives, how would be left?
olga_2 [115]

Answer:

75 g

Explanation:

1 half life = 600/2 = 300g

2 half life = 300/2 = 150g

3 half life = 150/2 = 75g

5 0
2 years ago
Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w
jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, COCl_2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:  

CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The value of K_c for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which p_{CO}=p_{Cl_2}=0.265atm and p_{COCl_2}=0.000atm ?

<u>Answer:</u> The equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

<u>Explanation:</u>

The relation of K_c\text{ and }K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p = Equilibrium constant in terms of partial pressure

K_c = Equilibrium constant in terms of concentration = 5.79

\Delta n_g = Difference between gaseous moles on product side and reactant side = n_{g,p}-n_{g,r}=1-2=-1

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

T = Temperature = 570 K

Putting values in above equation, we get:

K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

                      CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

<u>Initial:</u>            0.265      0.265

<u>At eqllm:</u>        0.265-x    0.265-x        x

The expression of K_p for above equation follows:

K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}

Putting values in above equation, we get:

0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = (0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of Cl_2=(0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of COCl_2=x=0.008atm

Hence, the equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

6 0
3 years ago
If I have an unknown quantity of gas at a pressure of 0.72 atm, a volume of 22
Darina [25.2K]

Answer:

0.64 mol

Explanation:

Using ideal gas equation as follows;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question;

P = 0.72atm

V = 22 L

T = 30°C = 30 + 273 = 303K

n = ?

Using PV = nRT

n = PV/RT

n = (0.72 × 22) ÷ (0.0821 × 303)

n = 15.84 ÷ 24.88

n = 0.64 mol

8 0
3 years ago
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