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konstantin123 [22]
3 years ago
12

A large data sample of heights of US women is normally distributed with a mean height of 64.7 inches and a standard deviation of

2.6 inches.
What is the approximate probability that a randomly selected person in this sample is shorter than 62.1 inches? I need this tonight
Mathematics
1 answer:
mariarad [96]3 years ago
7 0

Answer:0.16

Step-by-step explanation:

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1. Ella has 7 rolls and 6 loose medium shirts. Each shirt costs $10. What is the value of her
weqwewe [10]

Answer:

the value of her medium shirts is $60 if Ella makes 100 more shirts her new value is $600

6 0
2 years ago
The width of a rectangle is the sum of the length and 1. The area of the rectangle is 20 units. What is the width, in units, of
IRISSAK [1]

Answer:

W=5

Step-by-step explanation:

W=Width=Length + 1

L = Length

Area = Length * Width = 20

Area = L * W = L * (L+1) = 20

Distribute the L:   L^2 + L = 20

Subtract 20 from both sides: L^2 + L -20 = 20-20

Simplify:  L^2+L-20=0

Factor (L-4)(L+5)=0

Solve using the zero property: L-4=0, L=4      L+5=0, L=-5

The two options for length are 4 and -5. Only 4 will work for L since it cannot be negative.   Width is Length + 1 = 5

6 0
3 years ago
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Answer:

the picture is blocked

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
There are 6 bricks laid end to end to form a row in a flower garden each brick is 7 1/3 inches long how long is the row of brick
JulsSmile [24]

Answer:

The answer is 44 inches.

Step-by-step explanation:

6×7 1/3 = 44

6 0
3 years ago
timothyis re-arranging his marbles collection. he has 5 identical blue marbles, five green and 3 black. he can fit excactly 5 ma
Lerok [7]
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are  blue-green-black.

Now the rest of the collection consists of

                    4 blue
                    4 green
                    2 black

and there's space for 2 more marbles in the case.

So the question really asks:  "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"

-- Well, there are 10 marbles all together. 
So the first one chosen can be any one of the 10,
       and for each of those,
the second one can be any one of the remaining 9 .

Total number of ways to pick 2 out of the 10  =  (10 x 9)  =  90 ways.

-- BUT ... there are not nearly that many different combinations
to wind up with in the case.    

The first of the two picks can be any one of the 3 colors,
             and for each of those,
the second pick can also be any one of the 3 colors. 

So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
6 0
2 years ago
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