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konstantin123 [22]

3 years ago

12

A large data sample of heights of US women is normally distributed with a mean height of 64.7 inches and a standard deviation of

2.6 inches.
What is the approximate probability that a randomly selected person in this sample is shorter than 62.1 inches? I need this tonight

1 answer:

mariarad [96]3 years ago

7 0

Answer:0.16

Step-by-step explanation:

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Suppose you deposit $12.50 into your savings account each week for 4 weeks and then withdraw $4.80 each week for the next two we

monitta

Answer:

The total change in the amount of money in my account is $ 9.60

Step-by-step explanation:

Given:

Amount of money deposited each week, $A_{d}=\$12.50$

Amount of money withdrawn each week, $A_{w}=\$4.80$

∴ Amount of money deposited in 4 weeks, $A_{dT}=A_{d}\times 4=12.50\times 4 = \$50$

∴ Amount of money withdrawn in 2 weeks, $A_{wT}=A_{w}\times 4=4.80\times 2 = \$9.6$

Now, amount of money left in the account is the difference of the two amounts.

So, amount left = $A_{dT}-A_{wT}=50-9.6=\$40.4$

Therefore, the total change in the amount of money in my account is given as:

Total change = Initial amount after 4 weeks - Final amount in the account.

Total change = $ 50 - $40.4 = $ 9.6

7 0

3 years ago

2. Ryan has nine 14-ounce bags of popcorn

Serjik [45]

Answer:

42

Step-by-step explanation:

9 times 14 equals 126

126 divided by 3 equals 42

3 0

3 years ago

Am i right or am i wrong

anastassius [24]

Answer:

it looks good to me

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A line perpendicular to a plane, would intersect the plane at one what

Elena L [17]

If by this you mean perpendicular bisectors, then they would intersect at one point.

5 0

3 years ago

f p(x) and q(x) are arbitrary polynomials of degreeat most 2, then the mapping< p,q >= p(-2)q(-2)+ p(0)q(0)+ p(2)q(2)defin

Natasha2012 [34]

We're given an inner product defined by

$\langle p,q\rangle=p(-2)q(-2)+p(0)q(0)+p(2)q(2)$

That is, we multiply the values of $p(x)$ and $q(x)$ at $x=-2,0,2$ and add those products together.

$p(x)=2x^2+6x+1$

$q(x)=3x^2-5x-6$

The inner product is

$\langle p,q\rangle=-3\cdot16+1\cdot(-6)+21\cdot(-4)=-138$

To find the norms $\|p\|$ and $\|q\|$ , recall that the dot product of a vector with itself is equal to the square of that vector's norm:

$\langle p,p\rangle=\|p\|^2$

So we have

$\|p\|=\sqrt{\langle p,p\rangle}=\sqrt{(-3)^2+1^2+21^2}=\sqrt{451}$

$\|q\|=\sqrt{\langle q,q\rangle}=\sqrt{16^2+(-6)^2+(-4)^2}=2\sqrt{77}$

Finally, the angle $\theta$ between $p$ and $q$ can be found using the relation

$\langle p,q\rangle=\|p\|\|q\|\cos\theta$

$\implies\cos\theta=\dfrac{-138}{22\sqrt{287}}\implies\theta\approx1.95\,\mathrm{rad}\approx111.73^\circ$

4 0

3 years ago