Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Hey there!
Assuming you meant
If so, follow these steps so it can be a little bit easier to solve
Firstly, we have to 
by 
on each of your sides
We get: 
Now, we have 
by 
on each of your sides
We get: 
± 
Therefore , your answer is: ±
Good luck on your assignment and enjoy your day!
~
40 and 60
40 = 20 x 2
60 = 20 x 3
GCF = 20
<span>the greatest number of teams coach can make is 20
each team can have 2 girls and 3 boys</span>
Answer:
x/9 < 27
x < 27(9)
x < 243
Step-by-step explanation:
D. -15
All I did was plug the numbers in
