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trapecia [35]
3 years ago
13

Four baskets contain scented soaps. The baskets contain 9, 9, 11, and 15 soaps. If the soaps are divided evenly among the basket

s, how many soaps will go in each basket? A.9 B.10 C.11 D.12
Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

11

Step-by-step explanation:

9+9+11+15 is 44 44/4 is 11

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2.2.PS-8 Find the value of x when 6 - 4x = 6x - 8x + 8. The value of x is​
Bess [88]

Answer:

X = -1

Step-by-step explanation:

6 - 4x = 6x - 8x + 8

-6.                      -6

-4x = -2x + 2

+2x.   +2x

-2x = 2

divide both sides by -2

x = -1

6 0
2 years ago
The coordinates of point P on a coordinate grid are (−5, −6). Point P is reflected across the y-axis to obtain point Q and acros
Llana [10]
Hey friend!
Let's figure this out!

P(−5, −6)
reflect about y axis
Q(5, -6)
reflect about x axis
R(5,6)


So that gives you the answer!
3. Q(−5, 6) and R(5, −6)



Hope this helped!
4 0
3 years ago
Read 2 more answers
38.Randy and Amy left school at the same time and began walking in oppo-
RideAnS [48]

Answer:

DISTANCE=RATE*TIME. THEREFORE

X=3.6*1/6+4.2*1/6 (1/6 HOUR=10 MIN)

X=.6+.7

X=1.3 KM IS HOW FAR THEY WIL BE APART AFTER 10 MINUTES.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How do I solve this problem?
Brrunno [24]
A. x=the cost of one lunch. 60.25=5x+3(x-5.25)

b. 60.25=5x+3x-15.75                    60.25+15.75=8x-15.75+15.75

 76=8x                  76/8=8x/8              9.50=x

A lunch is $9.50. If you are not sure, check my answers. Hope this helped.
8 0
3 years ago
Given the following observed and expected data (total of 1000), using chi-squared calculate a p-value that corresponds with this
finlep [7]

Answer:

The answer is "0.90>p>0.75."

Step-by-step explanation:

\text{Cinnabar vestigial} \ \ \ \ \ \ \ \ \ \ \ 384 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \  -6 36 \ \ \ \ \ \ \ \ \ \ \  0.092308\\\\

roof \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \  408 \ \ \ \ \ \ \ \ \ \ \  390  \ \ \ \ \ \ \ \ \ \ \  18 \ \ \ \ \ \ \ \ \ \ \  324  \ \ \ \ \ \ \ \ \ \ \ 0.830769\\\\\text{Cinnabar vestigial roof} \ \ \ \ \ \ \ \ \ \ \ \ \ 63 \ \ \ \ \ \ \ \ \ \ \ \ \  70\ \ \ \ \ \ \ \ \ \ \ \ -7 \ \ \ \ \ \ \ \ \ \ \  49 \ \ \ \ \ \ \ \ \ \ \  0.7\\\\\text{wild type} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 72  \ \ \ \ \ \ \ \ \ \ \  70  \ \ \ \ \ \ \ \ \ \ \ 2  \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \  0.057143\\\\

vestigial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 32 \ \ \  \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.257143\\\\

\text{Cinnabar roof} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  -1 \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \  1  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.028571\\\\\text{roof vestigial}  \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.2\\\\

\text{cinnabar}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \  5 \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \  -2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.8 \\\\

Total \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1000 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ 2.965934

Eight phenotypes were present.  

Df is provided also by a number of phenotypes -1 The degree of freedom

\to df = 8-1= 7

For p-value 0,9, Chi-square is 2.83;

The p-value of 0.75 is 4.5. Chi-square

Chi-sqaure value is observed at 2.965.

That means 0.90>p-value>0.75.

7 0
3 years ago
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