Answer:
h( x ) = ( x + 1 )^2 - 4 x(h)×(÷×1)^2-4
Answer:
4 ther are 4 line symmetery
Answer:
41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.
First we have to calculate the perimeter of 1st triangle.
Given:
a = 33 yards
b = 56 yards
c = 65 yards
Now we have to calculate the perimeter of 2nd triangle.
Given:
a = 26 yards
b = 49 yards
c = 38 yards
Now we have to calculate which triangle has greater perimeter and how much greater.
Therefore, 41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.
Step-by-step explanation:
(154-113)
41 yards bigger
Answer:
- 3⁷/2⁹
Step-by-step explanation:
- (-2÷3)⁻³ ÷ x = (9÷8)⁻²
- -(2⁻³)×3⁽⁻¹⁾ˣ⁽⁻³⁾ ÷ x = (3²)⁻²×(2⁻³)⁻²
- -2⁻³×3³÷x = 3⁻⁴×2⁶
- x = -2⁻³×3³ ÷ (3⁻⁴×2⁶)
- x = - 2⁻³⁻⁶×3³⁻⁽⁻⁴⁾
- x = -2⁻⁹×3⁷
- x = - 3⁷/2⁹
Answer:
<h3>C. 113°</h3>
Step-by-step explanation:
(7x - 1) + 79° = 21x + 8
• An exterior angle of a triangle is equal to the sum of its two interior opposite angles.
NRS = 21x + 8
