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alina1380 [7]
4 years ago
11

A metal sample is heated and placed into the water in a calorimeter at room temperature. Which statement best describes how the

calorimeter can be used to determine the specific heat capacity of the metal sample?
Chemistry
1 answer:
andre [41]4 years ago
6 0

Answer:

Energy transfers from the metal to the water and calorimeter until they are all at room temperature.

Explanation:

CHECK THE COMPLETE QUESTION BELOW;

A metal sample is heated and placed into the water in a calorimeter at room temperature. Which statement best describes how the calorimeter can be used to determine the specific heat capacity of the metal sample?

Energy transfers to the metal from the water and calorimeter until they are all at room temperature

. Energy transfers from the metal to the water and calorimeter until they are all at room temperature.

Energy transfers to the metal from the water and calorimeter until they all reach a single temperature.

Energy transfers from the metal to the water and calorimeter until they all reach a single temperature.

EXPLANATION;

Using calorimeter to determine the specific heat capacity of the metal sample can be associated to the theory of conservation of energy because heat which is a form of energy is been transfer of heat between the metal to the water and the calorimeter, this process will proceed till single temperature is attained.

The change in the amount of temperature of the water in the calorimeter is measured in order to get the difference in heat change of the calorimeter water.

CHANGE IN HEAT CAN BE CALCULATED USING THE FORMULA.

Q = cmΔT where Q is the change in heat , c is the specific heat capacity and ΔT is the change in temperature

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About 7.9 L.

Explanation:

We can utilize the ideal gas law. Recall that:

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Because the amount of carbon dioxide does not change, we can rearrange to formula to:
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Because the right-hand side stays constant, we have that:
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Hence substitute initial values and known final values:
\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ $^\circ$C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ $^\circ$C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}

Therefore, the final volume is about 7.9 L.

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As you move down group one of the periodic table, what happens to the atomic radii? They increase, because of the higher number
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The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t
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Answer:

Mass =  42.8g

Explanation:

4 NH 3 ( g ) + 5 O 2 ( g ) ⟶ 4 NO ( g ) + 6 H 2 O ( g )

Observe that every 4 mole of ammonia requires 5 moles of oxygen to obtain 4 moles of Nitrogen oxide and 6 moles of water.

Step 1: Determine the balanced chemical equation for the chemical reaction.

The balanced chemical equation is already given.

Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).

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Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.

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x = (1.9831 * 6 ) / 5

x = 2.37972 moles

Mass of H2O = Molar mass * Molar mass

Mass = 2.7972 * 18

Mass =  42.8g

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