A buffer solution contains an equivalent amount of acid and base. The pH of the solution with an acid dissociation constant (pKa) value of 3.75 is 3.82.
<h3>What is pH?</h3>
The amount of hydrogen or the proton ion in the solution is expressed by the pH. It is given by the sum of pKa and the log of the concentration of acid and bases.
Given,
Concentration of salt [HCOO⁻] = 0.24 M
Concentration of acid [HCOOH] = 0.20 M
The acid dissociation constant (pKa) = 3.75
pH is calculated from the Hendersons equation as,
pH = pKa + log [salt] ÷ [acid]
pH = 3.75 + log [0.24] ÷ [0.20]
= 3.75 + log (1.2)
= 3.75 + 0.079
= 3.82
Therefore, 3.82 is the pH of the buffer.
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Answer : The correct option is, (D) CO₂, BCl₃, and Fe³⁺
Explanation :
According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.
(a) 
It is a Lewis-acid because it can accepts electron pairs.
(b) 
It is not a Lewis-acid because it can not accepts electron pairs but it is a base because it can donates and accept hydrogen ion.
(c) 
It is a Lewis-acid because it can accepts electron pairs because it has an incomplete octet and an empty 2p orbital.
(d) 
It is a Lewis-acid because it can accepts electron pairs.
Hence, the ions which behave as Lewis acids are, CO₂, BCl₃, and Fe³⁺
<span>The mass of the nail would increase, because the iron is adding oxygen to its chemical composition. This would increase the overall mass. If the mass increases from 23.2g to 24.1g, then the increase would be the difference between the two masses, or 0.9g.</span>
Answer:
19.3 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 12.4 kg
Volume (V) = 642 mL.
Density (D) =.?
Next, we shall convert 12.4 kg to grams. This can be obtained as follow:
1 kg = 1000 g
Therefore,
12.4 kg = 12.4 × 1000
12.4 kg = 12400 g
Therefore, 12.4 kg is equivalent to 12400 g.
Finally, we shall determine the density of the gold as follow:
Density is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) / volume (V)
D = m/V
With the above formula, the density of gold can easily be obtained as follow:
Mass (m) = 12400 g
Volume (V) = 642 mL.
Density (D) =.?
D = m/V
D = 12400/642
D = 19.3 g/mL
Therefore, the density of hold is 19.3 g/mL
Protons are one of the fully stable parts of matter