Question

If 4.65 LL of CO2CO2 gas at 22 ∘C∘C at 793 mmHg mmHg is used, what is the final volume, in liters, of the gas at 35 ∘C∘C and a pressure of 743 mmHg mmHg , if the amount of CO2CO2 does not change?

Answer 1

Answer:

About 7.9 L.

Explanation:

We can utilize the ideal gas law. Recall that:

$\displaystyle PV = nRT$

Because the amount of carbon dioxide does not change, we can rearrange to formula to:
$\displaystyle \frac{PV}{T}= nR$

Because the right-hand side stays constant, we have that:
$\displaystyle \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = nR$

Hence substitute initial values and known final values:
$\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ ^\circ C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ ^\circ C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}$

Therefore, the final volume is about 7.9 L.