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snow_tiger [21]
3 years ago
6

Birth control pills have a theoretical annual efficacy of 99.5%, but a real-worls efficacy of only 95%. If a college student tak

es the pill for the four years she is in college, what is the probability that she will become pregnant at least once using the theoretical efficacy rate?
A. 0

B. 0.005

C. 0.020

D. 0.185
Mathematics
1 answer:
shutvik [7]3 years ago
3 0

Answer:In my opinion B.0.005 is the correct answer

Step-by-step explanation:

hope it will help you

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Select the correct answer.
Dmitry [639]

Answer:

C

Step-by-step explanation:

An undefined slope means that the line is vertical and parallel to the y- axis.

A vertical line has equal x- coordinates of the points it passes through.

The only pair where the x- coordinates are equal are

(- 3, - 3) and (- 3, 3) ← undefined slope → C

6 0
4 years ago
Find the missing side round your answer to the nearest tenth
kap26 [50]
Use trigonometric ratios.
Use angle(19)
Adjacent side of angle measure 19 is X
The hypotenuse is 21.
Use the cosine
Cos(19)=x/21

Plug in calculator
(21)cos(19)=19.85

Round to the nearest tenth. Which means the 8 rounds up to 9.

Answer: 19.9
7 0
3 years ago
State whether the given measurements determine zero, one, or two triangles. A = 58°, a = 25, b = 28
Pavlova-9 [17]
I think the answer is one triangle not for sure though
6 0
3 years ago
Read 2 more answers
What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12
Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, <u>2 is our minimum and 17 is our maximum.</u>

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5

<u>The median is 12.5.</u>

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6

<u>The first quartile is 6.</u>

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15

<u>The third quartile is 15.</u>

3 0
3 years ago
Find the sum 3 3/5 and 2 1/2
Gre4nikov [31]
6 1/10 because 3 3/5 equals 3 6/10 and 2 1/2 equals 2 5/10. 3 6/10 plus 2 5/10=6 1/10

3 0
3 years ago
Read 2 more answers
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