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Ad libitum [116K]
3 years ago
15

What is the iron (ll) ion? How does it differ from the iron (lll) ion?

Physics
1 answer:
DaniilM [7]3 years ago
8 0
Iron III ion is an iron ion with a +3 charge. If iron bonded with oxygen, it would form Fe2O3 which is rust. In this case, the oxidation number on Fe is +3 and it is -2 on oxygen. This would be called iron (III) oxide. 

<span>The oxidation number of an ion times the number of the ions must equal zero when added together in a molecule with no charge. In this case, there are 2 iron molecules and each has a positive 3 charge. 2x3=6. There are three oxygen molecules each with a negative 2 charge. 3x-2=-6. 6+-6=0</span>
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What kind of reaction typically has a carbon compound and oxygen as
Anna11 [10]

Answer:

Answer would be  C because combustion does the process of heat. Oxygen is a reactant in a combination reaction, which always produces energy in the form of heat and light. Carbon burns in the presence of oxygen to give carbon dioxide.

3 0
3 years ago
Four wires are made of the same highly resistive material, cut to the same length, and connected in series. Wire 1 has resistanc
Paraphin [41]

Answer:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

Explanation:

The 4 wires are connected in series: this means that the same current flow through them, and the voltage of the battery, V0, is equal to the sum of the voltages on each individual resistor:

V_0=V_1+V_2+V_3+V_4

Also, the equivalent resistance of the series circuit is

R_{eq}=R_1+R_2+R_3+R_4

The voltage V2 across wire 2 is given by Ohm's law:

V_2 = R_2 I (1)

where I is the total current in the circuit, which is given by:

I=\frac{V_0}{R_{eq}}=\frac{V_0}{R_1+R_2+R_3+R_4}

Substituting this into eq. (1), we find an expression for V2:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

8 0
3 years ago
A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of th
Ber [7]

Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

Electron mobility, u = 3900

Hole mobility, h = 1900

Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)

R = 1 /0.0001831

R = 5461.4964 ohm /cm

5461.4964 / 10000

0.546 ohm / μm

7 0
3 years ago
r was thirsty and decided to mix up a pitcher of lemonade. She put lemon juice, water, and sugar into a pitcher and stirred it t
slamgirl [31]
She could tell by how many components she put in. The compounds, are like the ingredients. The Mixture is all the ingredients stirred together.
7 0
3 years ago
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Which element is the main component of<br> steel and the most widely used of all metals
Blizzard [7]

Answer:

iron

Explanation:

8 0
2 years ago
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