Equations of motion (EoM) use EoM <span>v2=u2+2ax</span> to establish velocities at positions shown in blue in drawing from EoM v=u+at for final 1 second of flight time, we can say v=u+g(1) <span><span>2gH−−−−√</span>=<span><span>2g1625H</span>−−−−−−√</span>+g</span><span> then, solve for H [in terms of g]
</span>
Answer:
it can kill you cell and win you kill you no cell no life
Explanation:
Answer:
A:7.2
B:14.25
C:1.45
D:10.3
E:2.9
F:20.88
Explanation:
Let
be the velocity and
be the angle between the velocity and ground.
Question A:
Horizontal component of velocity is given by
.
So,horizontal component is 
Question B:
Vertical component of velocity is given by
.
So,vertical component is 
Question C:
Time required is given by 
Question D:
Maximum height is given by 
Question E:
Time of flight is twice the time required to reach maximum height=
.
Question F:
The distance between the player and ball after landing is called range and is given by 

Energy of one photon = kinetic energy of photoelectron + work function energy of metal.
Intensity of radiation is proportional to the number of photons arriving per second