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scoray [572]
2 years ago
8

Help please!!! Physics circular motion

Physics
1 answer:
svp [43]2 years ago
6 0

Answer:

2. 3.1415 m/s

3. 0.63m

4. 0.006 m/s^2

Explanation:

2. v=(2*pi*r))/T, put in values and solve.

3. Circumference=2*pi*radius, radius is 0.1m, plug in and solve.

4. a=(v^2)/r, (don't worry about converting to meters, since units are the same in kilometers, they will cancel out) plug in values and solve.

That's it!

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HELP!!! 30 POINTS+BRAINLIEST!!!!!QUICK!!
tia_tia [17]

Answer:

A:7.2ms^{-1}

B:14.25ms^{-1}

C:1.45sec

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F:20.88m

Explanation:

Let v be the velocity and \alpha be the angle between the velocity and ground.

Question A:

Horizontal component of velocity is given by vcos(\alpha ).

So,horizontal component is 16\times cos(63)=16\times 0.45=7.2ms^{-1}

Question B:

Vertical component of velocity is given by vsin(\alpha ).

So,vertical component is 16\times sin(63)=16\times 0.89=14.25ms^{-1}

Question C:

Time required is given by \frac{\text{vertical component of velocity}}{g}}=\frac{14.25}{9.8}=1.45 seconds

Question D:

Maximum height is given by \frac{\text{vertical component of velocity}^{2}}{2g}}=\frac{203.06}{19.6}=10.3m

Question E:

Time of flight is twice the time required to reach maximum height=2\times 1.45=2.9 seconds.

Question F:

The distance between the player and ball after landing is called range and is given by \text{horizontal component of velocity}\times \text{time of flight}=7.2\times 2.9=20.88m

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Energy of one photon = kinetic energy of photoelectron + work function energy of metal.
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