The half-life of gold-198 is 2.77 days
Given:
mass of gold sample = 200-gram
mass of decay sample = 160 grams
time taken to decay = 6.25 days
To Find:
the half-life of gold-198
Solution: The amount of time it takes to disintegrate by half an initial amount. For a given reaction, a reactant's half-life t1/2 is the time it takes for its concentration to reach a value which is the arithmetic mean of its initial and final (equilibrium) value.
Since Au-198 is 200 g originally and it decays to 160 g, so 40g left
the fraction decay is 40/200 = 0.2
the time base is 6.25 days
ln0.2/6.25 = -0.25
k=ln2/half life therefore half-life = ln2/k = ln2/0.25
half life = 2.77 days
So, half life of gold is 2.77 days
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<h3><u>Answer;</u></h3>
a. CH3CO2H
<h3><u>Explanation;</u></h3>
- An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons. In other words an Arrhenius acid increases the concentration of H+ in aqueous solution.
- Acetic acid (CH3CO2) dissociates in aqueous solution to form hydrogen ions (H⁺) and acetic anion (CH₃COO⁻). Therefore, it is an Arrhenius acid.
- The equation of dissociation;
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).
Answer:
a
The condensed structural formula for methane is
b
The condensed structural formula for ethane is
c
The condensed structural formula for pentane is
d
The diagram for the structural formula for cyclopropane is shown on the first uploaded image
Explanation:
38 g / (3 x 10^23 molecules) * 6,02x10^23 molecules/mol = 76,25 g/mol.
In order to find the amount of atoms you have to find the moles then multiply by Avogadro's Constant (L)
mol =
=
= 3.73 mol
Number of atoms of Cu = mol × L
= 3.73 mol × (6.02 × 10²³)
= 2.245 × 10²⁴ atoms of copper
