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2 years ago

I have four questions if you will answer them I will Venmo you $10

Mathematics

2 answers:

Nataliya [291]2 years ago

8 0

Photomath helps a lot

almond37 [142]2 years ago

4 0

You should use this app called photomath!! it will give you the answer to the equation and there is a show work option and if you press it, it will show the work for u :)

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Anybody help please hm

Sati [7]

The answer should be C

4 0

2 years ago

Write out the form of the partial fraction decomposition of the function (as in this example). do not determine the numerical va

neonofarm [45]

$\frac{x^{4}-2x^{3}+x^{2}+7x-5}{x^{2}-2x+1} = x^{2}+\frac{a}{x-1}+\frac{b}{(x-1)^{2}}$
It looks like your first selection (a) is appropriate.

7 0

3 years ago

I’m really confused please help

sveticcg [70]

Answer: probly d

Step-by-step explanation:

a ,b ,and c are subtracting makeing it hard top get something that was not in the problem

6 0

2 years ago

The domain is the set of all values a function will accept as _____.

Marina86 [1]

Answer:

... inputs.

Step-by-step explanation:

A function is a map of inputs to outputs. The domain of a function is the set of inputs for which outputs are defined.

8 0

2 years ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

Step-by-step explanation:

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

Step-by-step explanation:

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$

Area of ΔBEF:

$\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18$

5 0

2 years ago