Answer:
The mixtures are not proportional.
3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.
its =3
Step-by-step explanation:
The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.
Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5
Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.
Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4
Therefore, the mixtures are not proportional.
Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.
So,
⇒ 12 + x = 15
⇒ x = 3 fluid ounces.
Therefore, 3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture. (Answer
The customer gave me:
-- a ticket worth $5
-- a ticket worth $2
-- a bill worth $100
Total. . . . . . .$107
I gave him:
-- some gas worth $17.01
-- a ticket worth $ 5
-- two $1 tickets $ 2
-- a ticket worth $ 3
Total. . . . . . . .$27.01
The total value of everything we trade has to be equal.
I owe him ( $107.00 - $27.01 ) = $79.99 in change
