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2 years ago

The diameter of a circle is 3 ft, what's the area to the nearest tenth?

Mathematics

1 answer:

xeze [42]2 years ago

6 0

Answer:

1.5

Step-by-step explanation:

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I need help asap someone please help me i dont understand this question so can someone help me

eduard

Answer:

we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

Step-by-step explanation:

Given the expression

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}$

$=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}$

cancel the common factor: 2

$=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}$

cancel the common factor: p

$=\frac{2p+1}{p^2\left(4p^2-1\right)}$

$=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}$

cancel the common factor: 2p+1

$=\frac{1}{p^2\left(2p-1\right)}$

Expanding

$=\frac{1}{2p^3-p^2}$

Thus, we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

7 0

3 years ago

An internet book company charges $7 for each paperback plus $2.75 for shipping and handling per order

Leto [7]

Step-by-step explanation:

is it addition I got 9.75

5 0

3 years ago

What is the 32nd term of the arithmetic sequence where a1 = 14 and a13 = -58?

liq [111]

The nth term of an arithmetic sequence is found from:
$n_{th}\ term=a+(n-1)d$
Plugging in the given values, we get for the 13th term:
-58=14+12d
12d =-58 - 14 = -72
d = -6
So, the 32nd term is:
$a_{32}=14+(32-1)-6=-172$

5 0

3 years ago

Write an expression in factored form for the polynomial of least possible degree graphed below.

dexar [7]

Answer:

- 1/64 (x+4)² (x-3) (x-4) = 0

Step-by-step explanation:

f(x) = a (x+4)²(x-3)(x-4) ... curve touch (-4,0) and not cross x axis

x=0 f(x) = -3

a (4)² * (-3) * (-4) = -3

a = - 1/64

- 1/64 (x+4)² (x-3) (x-4) = 0

5 0

3 years ago

Suppose that the function g is defined, for all real numbers, as follows.

svetoff [14.1K]

Answer:

a) g(-2) = 0

b) g(-1) =1

c) g(4) = 2

Step-by-step explanation:

Given data

$g(x) = \frac{-1}{4x+1} if x < -2$

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

$g(x) = 2 if x >2$

Step( i ):-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

put x = -2

$g(-2) = -(-2+1)^{2} +1 = -(-1)^{2}+1 = -1+1 =0$

g(-2) = 0

Step(ii):-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

Put x = -1

$g(-1) = -(-1+1)^{2} +1 = -(0)^{2}+1 = -0+1 =1$

g(-1) =1

Step(iii):-

$g(x) = 2 if x >2$

g(4) = 2

7 0

3 years ago