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Shalnov [3]
3 years ago
10

If someone feels intent on fighting with you, what should you do to prevent getting into a fight?

Physics
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

avoid verbal argument and walk away

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A shark is cruising at 4 m/s when it sees a fish straight
Oksanka [162]

Answer:

Distance, S = 13m

Explanation:

Given the following data;

Initial velocity, u = 4m/s

Final velocity, v = 9m/s

Time, t = 2 seconds

To find the distance, S;

First of all, we would determine the acceleration of the shark.

Acceleration = (v - u)/t

Acceleration = (9 - 4)/2

Acceleration = 5/2

Acceleration = 2.5m/s²

Now, to find the distance we would use the second equation of motion

S = ut + ½at²

Substituting into the equation, we have

S = 4(2) + ½*2.5*2²

S = 8 + 1.25*4

S = 8 + 5

Distance, S = 13m

3 0
4 years ago
Which of the following describes wavelength?
blagie [28]
D. The number of wave that pass a point in a given amount of time
3 0
4 years ago
Calculate the speed (in m/sec) of a wave with a wavelength of 2.1 meters and a period of 9.4 second.
Lorico [155]

Wave speed = (wavelength) x (frequency)

We know the wavelength, but we don't know the frequency. How can we find the frequency ?  "Here frequency frequency."

We know the period, and frequency is just (1 / period).  So . . .

Wave speed = (wavelength) / (period)

Wave speed = (2.1 meters) / (9.4 seconds)

Wave speed = (2.1 / 9.4) m/s

<em>Wave speed = 0.223 m/s</em>

8 0
3 years ago
A crate of 890 kg gets raised to a height of 2.1m. Calculate the crate's gravitational potential energy.​
mars1129 [50]

Answer:

18,316.2

Explanation:

The formula for GPE is mgh, where

M = Mass of the object

G = Acceleration due to gravity (9.8 m/s^2 on Earth)

H = Height above ground

890 × 9.8 × 2.1 = 18,316.2

4 0
3 years ago
Read 2 more answers
A large aquarium of height 6 m is filled with fresh water to a depth of D = 1.50 m. One wall of the aquarium consists of thick p
Vesnalui [34]

Answer

given,

height of aquarium = 6 m

Depth of fresh water = D = 1.50 m

horizontal length of the aquarium(w) = 8.40 m

total force increased when liquid is filled to depth = 4.30 m

g = 9.81 m/s²

ρ = 998 Kg/m³

force in the aquarium.

dF = PdA

F = \int PdA

F = \int \rho\ g\ y\ (wdy)

F = \rho\ g\ w \int ydy

F = \rho\ g\ w\dfrac{y^2}{2}

F = \dfrac{\rho\ g\ w\ y^2}{2}

At D = 1.5 m

F = \dfrac{980\times 9.8\times 8.4\times 1.5^2}{2}

F = 9.08 x 10⁴ N

At D = 4.30 m

F = \dfrac{980\times 9.8\times 8.4\times 4.3^2}{2}

F = 7.46 x 10⁵ N

Total force on the wall increased by

ΔF  = 74.6 x 10⁴ - 9.08 x 10⁴

ΔF  = 65.52 x 10⁴ N

5 0
3 years ago
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