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Snezhnost [94]
3 years ago
5

Which of the following describes wavelength?

Physics
1 answer:
blagie [28]3 years ago
3 0
D. The number of wave that pass a point in a given amount of time
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A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?
ElenaW [278]
R=ut+gt^2/2
r- displacement (height to find)
u - initial speed (zero)
t - time taken

r=0*5.8 + 10*5.8^2 /2 = 168.2 meters
8 0
3 years ago
أسقط عامل حجرة من سطح بناية سقوطأ حرة. أوجد ما يلي :
Ilia_Sergeevich [38]

Answer:

??? i don't no what you just said

Explanation:

7 0
2 years ago
A sound wave with a frequency of 400 Hz is moving through a solid object. If the wavelength of the sound wave is 8 m, what is th
Paraphin [41]

Answer:

v = 3200 m/s

Explanation:

As we know that the frequency of the sound wave is given as

f = 400 Hz

wavelength of the sound wave is given as

\lambda = 8 m

so now we have

speed = wavelength \times frequency

so we will have

v = (8m) \times (400 Hz)

v = 3200 m/s

4 0
3 years ago
if you put a pencil in a cup of water, it looks as if it is broken and larger in the water. This is because light waves
vladimir1956 [14]

Answer:

When light enters from air to water i.e. it is moving from rarer to denser medium, it changes its original path as there is a change of speed of light and deflects itself towards the normal. This is known as the refraction of light and this is why a pencil in a cup of water looks as if it is broken and larger.

Explanation:

5 0
3 years ago
An aluminum wire having a cross-sectional area equal to 2.20 10-6 m2 carries a current of 4.50 A. The density of aluminum is 2.7
Kazeer [188]

Answer:

The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

Explanation:

We can find the drift speed by using the following equation:

v = \frac{I}{nqA}

Where:

I: is the current = 4.50 A

n: is the number of electrons

q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C

A: is the cross-sectional area = 2.20x10⁻⁶ m²

We need to find the number of electrons:

n = \frac{6.022\cdot 10^{23} atoms}{1 mol}*\frac{1 mol}{26.982 g}*\frac{2.70 g}{1 cm^{3}}*\frac{(100 cm)^{3}}{1 m^{3}} = 6.03 \cdot 10^{28} atom/m^{3}                  

Now, we can find the drift speed:

v = \frac{I}{nqA} = \frac{4.50 A}{6.03 \cdot 10^{28} atom/m^{3}*1.6 \cdot 10^{-19} C*2.20 \cdot 10^{-6} m^{2}} = 2.12 \cdot 10^{-4} m/s              

Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

I hope it helps you!      

4 0
2 years ago
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