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3 years ago

A push or pull that gives energy to an ob-

Physics

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

The answer is a force

Lina20 [59]3 years ago

7 0

The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

A force is a push or pull that gives energy to an object, causing that object to start moving, stop moving, or change its motion.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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Products must equal which in a chemical reaction?

Evgesh-ka [11]

I think it is reactants

3 0

3 years ago

William Tell shoots an apple from his son's head. The speed of the 102-g arrow just before it strikes the apple is 26.7 m/s, and

xxMikexx [17]

To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.

By definition the conservation of momentum tells us that, $m_1V_1+m_2V_2 = (m1+m2)V_f$

To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,

$t= \sqrt{\frac{2h}{g}}$

The linear velocity of an object is given by

$V=\frac{X}{t}$

Replacing the equation of time we have to,

$V_f = \frac{X}{t}\\V_f =\frac{X}{\sqrt{\frac{2h}{g}}}\\V_f = \frac{6.9}{\sqrt{\frac{2(1.85)}{9.8}}}\\V_f = 11.23m/s$

Velocity two is neglected since there is no velocity of said target before the collision, thus,

$m_1V_1 = (m1+m2)V_f$

Clearing for m_2

$m_2 = \frac{m_1V_1}{V_f}-m_1\\m_2 = \frac{(0.102)(26.7)}{11.23}-0.102\\m_2 = 0.1405KG= 140.5g$

8 0

3 years ago

2.19 The drag characteristics of a blimp traveling at 4 m/s are to be studied by experiments in a water tunnel. The prototype is

Naily [24]

Answer:

$Vm=0.894m/s$

Explanation:

From the question we are told that

Velocity if travel $v=4m/s$

Diameter of prototype $d_1=20m$ and $d_2=110m$

Scale ratio= $\frac{1}{20}$

Generally Velocity of of the model using Froud's model is mathematically given as

$Fm=Fp$

$\frac{Vm}{\sqrt{Lmg}} =\frac{Vp}{\sqrt{Lpg}}$

$Vm=Vp*\frac{Vp}{\sqrt{Lpg} }$

$Vm=4*\frac{1}{\sqrt{20}}$

$Vm=0.894m/s$

8 0

3 years ago

A machine lifts a 35 kg object doing 6860 J worth of work. How much power is produced by the machine if it lifts the object in 4

timofeeve [1]

Answer:

Explanation:

We need the power equation for this which is

P = Work/time

We have everything we need to solve this (the mass of the object is extra information):

P = 6860/4

P = 1715W

5 0

3 years ago

A current-carrying wire oriented north-south and laid over a compass deflects the compass 8° to the east. What is the magnitude

zhenek [66]

$2.8 \times 10^{-6}\ T$ is the magnitude of the magnetic field made by the current

Explanation:

Given data:

$\theta=8^{\circ}$

Magnetic field of earth, $B_{\text {earth}}=2 \times 10^{-5}\ \text {tesla}$

We need to find the magnetic field of wire, $B_{\text {wire }}$

The compass needle moves toward a direction of magnetic field. The current in wire makes a magnetic field in available space where the compass is on the ground. The vector sum of the Earth's magnetic field and the wire's magnetic field represents the net magnetic field, as shown in the attached drawing, expressing the angle:

$\tan \theta=\frac{B_{\text {wire}}}{B_{\text {earth}}}$

By substituting the given values, we get

$B_{\text {wire}}=\tan \theta \times B_{\text {earth}}=\tan 8^{\circ} \times 2 \times 10^{-5}=0.1405 \times 2 \times 10^{-5}$

$B_{\text {wire}}=0.28 \times 10^{-5}=2.8 \times 10^{-6}\ T$

4 0

3 years ago