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3 years ago

6

108 students went on a field trip. Three buses were filled and 12 students traveled in cars. How many students were in each bus?

2 answers:

il63 [147K]3 years ago

5 0

Answer :23

Step-by-step explanation:

Nesterboy [21]3 years ago

3 0

Answer:

32 students per bus

Step-by-step explanation:

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Which of the following is an odd function

nika2105 [10]

Given the functions

(a) f(x) = x³ + 5x² + x

(b) f(x) = x² + x

(c) f(x) = -x

Function (a)

f(-x) = (-x)³ + 5(-x)² + (-x)

= -x³ + 5x² - x

= -(x³ - 5x² + x)

The function is neither even nor odd.

Function (b)

f(-x) = (-x)² + (-x)

= -(-x² + x)

The function is neither even nor odd.

Function (c)

f(-x) = -(-x)

= x

= -f(x)

Because f(-x) = -f(x) the function is odd.

Answer: f(x) = -x is an odd function.

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3 years ago

Consider the following function G(x) = 2 (x-3)<br><br><br> Find G(4) + G (5)

NNADVOKAT [17]

Answer: 6

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Alja [10]

5.95 for everything 4.5 add 1.45

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3 years ago

A rectangle’s perimeter and its area have the same numerical value. The width of the

Zolol [24]

Step-by-step explanation:

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4 years ago

Simplify: (8t4 + 6 )+(914 – 2ť + 6t? – 6 )

vekshin1

Answer:t

2⋅(17t 2 −2t+6)

Step-by-step explanation:

v(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

2

:

Equation at the end of step

2

:

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

3

:

Equation at the end of step

3

:

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

4

:

Equation at the end of step

4

:

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

2

:

Equation at the end of step

2

:

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

3

:

Equation at the end of step

3

:

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

4

:

Equation at the end of step

4

:

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

2

:

Equation at the end of step

2

:

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

3

:

Equation at the end of step

3

:

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

4

:

Equation at the end of step

4

:

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

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3 years ago