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3 years ago

What is the solution to 4x+6 518? XS3 XS6 X548 X596

Mathematics

2 answers:

vovikov84 [41]3 years ago

6 0

Answer:

x ≤ 3

Step-by-step explanation:

So first we need to subtract 6 from both sides of the equation to get 4x ≤ 12

Then we need to divide both sides by 4 to get x ≤ 3

andreev551 [17]3 years ago

5 0

The second one you are welcome

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Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

4 years ago

A toy baseball and bat cost $1.50 together. The bat costs $1.00 more than the baseball. How much does the baseball cost?

Nataly [62]

$0.50 is the answer. If the bat is $1.00 more than the baseball, you would subtract that from the total cost which is $1.50 so the answer would be $0.50.

4 0

3 years ago

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The total snowfall in Burke, Virginia, this January was 7 1/4 in. In February, 20% more snow fell than in January.

Elis [28]

I think the answer is 7 2/9

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3 years ago

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A circular sector has a central angle of π6 radians and a radius of 9 ft.

ohaa [14]

Answer:

$\approx \: 21.2 \: {ft}^{2}$

Step-by-step explanation:

$central \: \angle = \frac{\pi ^{c} }{6} = 30 \degree \\ \\ area \: of \: the \: sector = \frac{30 \degree}{360 \degree} \times \pi {(9)}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 81 \\ \\ = \frac{1}{12} \times 254.34 \\ \\ = 21.195 \: {ft}^{2} \\ \\ \approx \: 21.2 \: {ft}^{2}$