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3 years ago

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Suzanne ran 334 miles in the morning and 412 miles in the afternoon. How many kilometers did she run altogether? Assume 1 mile

= 1.6 kilometers. Enter your answer, as a decimal, in the box

1 answer:

morpeh [17]3 years ago

8 0

1193.6 because 334+412=746 and 746*1.6=1193.6

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Please help me someone

Brut [27]

Answer: C

Step-by-step explanation: Consider a triangle with points A, B and C. You must create a perpendicular bisector of AB and then a perpendicular bisector of BC that crosses each other. Then you must label the center of that point D, and then using a compass tool, create a circle around the triangle.

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2 years ago

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A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa

diamong [38]

Answer:

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}= \mu_D$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C,D$

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p=4$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0

3 years ago

PLEASE HELP!!!!! How many 4-digit numbers divisible by 5, all of the digits of which are even, are there?

saul85 [17]

Answer:

I assume you know Arithmetic Progression .

so, we have to find the first and last 4-digit number divisible by 5

first = 1000 , last = 9990

we have a formula, $a_{n}$ = a + (n-1)d

here, $a_{n}$ is the last 4-digit number divisible by 5.

n is the number of 4-digit even numbers divisible by 5

d is the common difference between the numbers, which is 10 in this case

a is the first 4-digit number divisible by 5

9990 = 1000 + (n-1)*10

899 = n-1

n = 900

Hence, there are 900 4-digit even numbers divisible by 5

7 0

3 years ago

Please help and thank you

Anna11 [10]

2 servings because one serving is 4%, so you would need would need to double that, or multiply it by two.

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3 years ago

How to find the square root and cube root of a number?

tiny-mole [99]

To find<span> the </span>cube root of a number<span>, you want to </span>find <span>some </span>number<span> that when multiplied by itself twice gives you the original </span>number<span>. In other words, to </span>find <span>the </span>cube root<span> of 8, you want to </span>find<span> the </span>number<span> that when multiplied by itself twice gives you 8. The </span>cube root<span> of 8, then, is 2, because 2 × 2 × 2 = 8.</span>

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3 years ago

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