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MrRissso [65]
3 years ago
9

Select the correct answer. Five marbles roll down a ramp. Each marble reaches the bottom of the ramp at a speed of 3 meters/seco

nd. Which marble has the highest kinetic energy at the bottom of the ramp? The table lists the mass of each marble. Marble 1 Marble 2 Marble 3 Marble 4 Marble 5 10 g 20 g 25 g 40 g 30 g A. Marble 1 B. Marble 2 C. Marble 3 D. Marble 4 E. Marble 5
Physics
2 answers:
Lorico [155]3 years ago
8 0

Answer:

40 g

Explanation:

The energy possessed by the body due to its motion is called its kinetic energy.

The formula for the kinetic energy is given by

K = \frac{1}{2}mv^{2}

All the marbles having same speed but different mass.

So, Kinetic energy is directly proportional to the mass of the body keeping velocity constant.

The marble has maximum mass has highest kinetic energy .

So, the marble having mass 40 g has highest kinetic energy.

MA_775_DIABLO [31]3 years ago
4 0

Kinetic energy = (1/2) * mass * velocity

Marble 1 = (1/2) * 10 * 3 = 15 Joules

Marble 2 = 30 J

Marble 3 = 37.5 J

Marble 4 = 60 J

Marble 5 = 45 J


Marble 4 has the most kinetic energy - D.


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My name is Ann [436]

Answer:

well, during reflection

angle of incident is equal to angle of reflection so if angles of incident is 23° , then angle of reflection is also equal to 23° .

so the total angle between the reflected and incident ray will be equal to angle of incidence plus angle of reflection

i.e. angle i + angle r = 23° + 23° = 46°

hence the required angle is 46°

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em> </em><em>.</em>

4 0
3 years ago
An electron in an electron gun is accelerated from rest by a potential of 25 kV applied over a distance of 1 cm.
podryga [215]

Answer:

9.38\times 10^7 m/s

Explanation:

We are given that

Potential ,V=25 kV=25\times 10^3 V

Distance,r =1 cm=\frac{1}{100}=0.01 m

1 m=100 cm

Mass of electron, m=9.1\times 10^{-31} kg

Charge, q=1.6\times 10^{-19} C

We have to find the final velocity of the electron.

Speed of electron,v=\sqrt{\frac{2qV}{m}}

Using the formula

v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 25\times 10^3}{9.1\times 10^{-31}}

v=9.38\times 10^7 m/s

Hence, the final velocity of the electron=9.38\times 10^7 m/s

3 0
4 years ago
What happens to the particles of matter vibrated by a wave after the wave passes through the matter
Mariulka [41]

Answer:

As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on.

Explanation:

5 0
3 years ago
The use of force to move an object is<br> I
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Answer:

and unbalanced force

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5 0
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ElenaW [278]

Answer:

The answer to this is

6600 Hz to 19,800 Hz

Explanation:

The shape of the human ear is analogous to a closed ended pipe hence

we have λ = 4L or wavelength = 4 * length of the child ear

The frequency  c/λ  where c = speed of sound = 343 m/s

hence the child's audible range is multiples of 343/(4*0.13) =6600Hz

or 13200 Hz or 19,800 Hz

The generally quoted range of human hearing is 20 Hz to 20 kHz

7 0
3 years ago
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