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MrRissso [65]
3 years ago
9

Select the correct answer. Five marbles roll down a ramp. Each marble reaches the bottom of the ramp at a speed of 3 meters/seco

nd. Which marble has the highest kinetic energy at the bottom of the ramp? The table lists the mass of each marble. Marble 1 Marble 2 Marble 3 Marble 4 Marble 5 10 g 20 g 25 g 40 g 30 g A. Marble 1 B. Marble 2 C. Marble 3 D. Marble 4 E. Marble 5
Physics
2 answers:
Lorico [155]3 years ago
8 0

Answer:

40 g

Explanation:

The energy possessed by the body due to its motion is called its kinetic energy.

The formula for the kinetic energy is given by

K = \frac{1}{2}mv^{2}

All the marbles having same speed but different mass.

So, Kinetic energy is directly proportional to the mass of the body keeping velocity constant.

The marble has maximum mass has highest kinetic energy .

So, the marble having mass 40 g has highest kinetic energy.

MA_775_DIABLO [31]3 years ago
4 0

Kinetic energy = (1/2) * mass * velocity

Marble 1 = (1/2) * 10 * 3 = 15 Joules

Marble 2 = 30 J

Marble 3 = 37.5 J

Marble 4 = 60 J

Marble 5 = 45 J


Marble 4 has the most kinetic energy - D.


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Salsk061 [2.6K]

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First of all, we need to find the angular velocity of the blade at time t = 0.200 s. This is given by

\omega_f = \omega_i + \alpha t

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\omega_i = 0.300 rev/s is the initial angular velocity

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Substituting t = 0.200 s, we find

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2) 2.25 m/s^2

The tangential acceleration of a point rotating at a distance r from the centre of the circle is

a_t = \alpha r

where \alpha is the angular acceleration.

First of all, we need to convert the angular acceleration into rad/s^2:

\alpha = 0.895 rev/s^ \cdot 2 \pi =5.62 rad/s^2

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3) 3.6 m/s^2

The centripetal acceleration is given by

a=\frac{v^2}{r}

where

v is the tangential speed

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We already calculate the tangential speed at point a):

v = 1.2 m/s

while the distance of a point at the end of the blade from the centre is

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Therefore, the centripetal acceleration is

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7 0
3 years ago
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Answer:

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We have given electric field at a point is E = 260000 N/C

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So force will be equal to F=260000\times -6.7=-1742000N

So electric force on the charge will be equal to -1742000 N

3 0
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