![\boxed{pd\sqrt[4]{48p^3d}}](https://tex.z-dn.net/?f=%5Cboxed%7Bpd%5Csqrt%5B4%5D%7B48p%5E3d%7D%7D)
<h2>
Explanation:</h2>
Here we have the following expression:
![\sqrt[4]{48p^7d^5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B48p%5E7d%5E5%7D)
So we need to simplify it:
![\sqrt[4]{48p^7d^5} \\ \\ \\ We \ can \ write: \\ \\ p^7=p^4\cdot p^3 \\ \\ d^5=d^4\cdot d \\ \\ \\ So: \\ \\ \sqrt[4]{48p^4\cdot p^3\cdot d^4\cdot d} \\ \\ \\ By \ property: \\ \\ \sqrt[n]{x^n}=x \\ \\ \\ Finally: \\ \\ \boxed{pd\sqrt[4]{48p^3d}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B48p%5E7d%5E5%7D%20%5C%5C%20%5C%5C%20%5C%5C%20We%20%5C%20can%20%5C%20write%3A%20%5C%5C%20%5C%5C%20p%5E7%3Dp%5E4%5Ccdot%20p%5E3%20%5C%5C%20%5C%5C%20d%5E5%3Dd%5E4%5Ccdot%20d%20%5C%5C%20%5C%5C%20%5C%5C%20So%3A%20%5C%5C%20%5C%5C%20%5Csqrt%5B4%5D%7B48p%5E4%5Ccdot%20p%5E3%5Ccdot%20d%5E4%5Ccdot%20d%7D%20%5C%5C%20%5C%5C%20%5C%5C%20By%20%5C%20property%3A%20%5C%5C%20%5C%5C%20%5Csqrt%5Bn%5D%7Bx%5En%7D%3Dx%20%5C%5C%20%5C%5C%20%5C%5C%20Finally%3A%20%5C%5C%20%5C%5C%20%5Cboxed%7Bpd%5Csqrt%5B4%5D%7B48p%5E3d%7D%7D)
<h2>Learn more:</h2>
Mathematical expressions: brainly.com/question/14200575#
#LearnWithBrainly
Let's figure this out. Step by step:
P / 6 = 9
P = 6(9)
P = 54 is your answer.
I hope this helps :)
3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191 those are some prime numbers :)
Answer: x = 6
Step-by-step explanation:
X - (-4) = 10
X + 4 = 10
X = 10 - 4 = 6