Among the students who did not make the honor roll. Then the relative frequency of having no curfew will be 7.
<h3>How to find the relative frequency?</h3>
Relative frequency is the ratio of the considered sub-group count to the total count. (so its frequency of the considered sub-group relative to the total frequency).
Curfew No Curfew No
Honor Roll: 18 10
No Honor Roll: 2 7
Among the students who did not make the honor roll.
Then the relative frequency of having no curfew will be 7.
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a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
Answer:
$830
Step-by-step explanation:
Samer's salary each month is $3,650. He spends $1,160 on rent. He breaks the rest of his earnings into 3 other monthly expenses. How much money was in each part?
Step 1
$3,650 - $1,160
= $2490
Step 2
He breaks the rest of his earnings into 3 other monthly expenses. How much money was in each part?
Hence,
$2490/3
= $830
The amount of money in each part = $830
Answer
80 i think because
Combine like terms: 28 + 12 = 40
0.5x = 40
Divide each side by '0.5'.
x = 80