Does the graph below represent a function? A. Yes

Is 3.02859 is a rational number

Margarita [4]

No this cannot be written into a fraction there for it is a non- rational number. hope i helped :))

5 0

2 years ago

Solve for t - 7/4 = 2/5 (t) t=

Lena [83]

-7/4:-1.75
2/5:0.4
-1.75=0.4t
-1.75/0.4=t
-4.375=t

Hope I helped you well, have a victorious day!

4 0

2 years ago

If two triangles have three congruent, corresponding

Tcecarenko [31]

Answer:

a pair of corresponding sides must be shown congruent

Step-by-step explanation:

The triangles are "similar" if corresponding angles are congruent. The triangles will only be "congruent" if corresponding sides are also congruent. The additional information needed is that there is one congruent pair of corresponding sides. (If there's one pair, all pairs of corresponding sides will be congruent.)

Having one pair of corresponding sides congruent would allow you to invoke either of the ASA or AAS congruence postulates.

5 0

2 years ago

The economics department has 40 applicants for their phd program and only 10 openings. how many different combinations of applic

lana66690 [7]

In a sequence of events, the total possible number of ways all events can performed is the product of the possible number of ways each individual event can be performed. Since there are 10 openings

P = 40 x 39 x 38 x 37 x 36 x 35 x 34 x 33 x 32 x 31 = 3.07599 x 10^15 different combinations

5 0

3 years ago

Suppose m is in the line given by the equation 6x-3y=7, and suppose n is the line perpendicular to m and passing Nd through the

stealth61 [152]

Answer:

The x co-ordinate o intersection of line k and n is $\frac{8}{11}$

Step-by-step explanation:

Given as :

The equation of line m is 6 x - 3 y = 7

So, in the standard form , line equation is

y = a x + c , where a is the slope

So, 6 x - 3 y = 7 can be written as

3 y = 6 x - 7

or, y = 2 x - $\frac{7}{3}$ ........1

So, slope of this line = a = 2

Now, The line n is perpendicular to line m and passing through line ( 6 , 2 )

So, Slope of line n = b

For , perpendicular lines , products of slope = - 1

Or, a × b = -1

∴ b = - $\frac{1}{a}$

I.e b = - $\frac{1}{2}$

So,equation of line n with slope b and passing through line ( 6 , 2 ) is

y - $y_1$ = b ( x - $x_1$ )

or, y - 2 = - $\frac{1}{2}$ ( x - 6 )

or, 2 × ( y - 2 ) = - 1 ( x - 6 )

or, 2 y - 4 = - x + 6

or, x + 2 y -10 = 0 ........2

Again, equation of line k with slope 5 and y intercept = 1

For y intercept , x coordinate = 0

y = c x + c

or, 1 = c× ( 0 ) + c

Or, c = 1

Or, equation of line k is

y = 5 x + 1 ..........3

Now intersection of line k and n is

put the value of y from eq 3 into eq 2

I.e x + 2 × ( 5 x + 1 )-10 = 0

Or, x + 10 x + 2 - 10 = 0

or, 11 x - 8 = 0

or 11 x = 8

∴ x = $\frac{8}{11}$

Hence The x co-ordinate o intersection of line k and n is $\frac{8}{11}$ Answer

4 0

3 years ago