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jonny [76]
3 years ago
11

1. what are valence electrons?

Physics
2 answers:
Aleks04 [339]3 years ago
6 0
<span>Valence electrons are electrons in the outermost shell available for bonding</span>
In-s [12.5K]3 years ago
3 0
For number one the answer would be B

I think the second one B, 24
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What do you think would happen to the force if the distance is cut in half and each of the masses is also cut in half
Rashid [163]

The formula for the force of gravity has  ( M₁ · M₂ / D² )  in it.

After the changes, the new force will have  ( 0.5M₁ · 0.5M₂ / (0.5D)² ) .

We can separate the new numbers from the original force, like this:

                         ( 0.5M₁ · 0.5M₂ / (0.5D)² ) 

                     =  ( 0.5 · 0.5 / (0.5)² ) times ( M₁ · M₂ / D² )

The first factor boils down to ' 1 '.  So, those changes would
leave the strength of the force unchanged.

That's what I think.
4 0
3 years ago
A car is traveling at 7.1m/s accelerates 4.3 m/s^2 to reach a speed of 16.0 m/s how long does it take for this acceleration to o
Bond [772]

<u>Answer</u>

2.06977 seconds


<u>Explanation</u>

Acceleration, a, is the rate of change of velocity

a = (v-u)/t

  where v and u are final and initial velocities respectively.

4.3 = (16.0 - 7.1)/t

4.3 = 8.9/t

t = 8.9/4.3

   = 2.06977 seconds

4 0
3 years ago
4) A force of 500 N acts on an area of 0.05m2. Find the pressure in Pascal.
snow_tiger [21]

Answer:

pressure = force ie 500 N divided by area ie 0.05m².

p=f by a

p= 500n divided by 0.05 m²

p= 10,000 pascal

6 0
3 years ago
A cart rolling down an incline that is 60 meters long. If the cart has a beginning speed of 2.0 m/s and it
fiasKO [112]

Answer:

4 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 2.0 m/s

v = 22 m/s

Find: a

v² = v₀² + 2aΔx

(22 m/s)² = (2.0 m/s)² + 2a (60 m)

a = 4 m/s²

3 0
3 years ago
PLEASE HELP A student climbs to the top of a press box where the cameras are. He wonders how many meters he is off of the ground
Feliz [49]

The height of the rail on top of the press box where the ball was dropped from is 11.025 m.

The given parameters:

  • Time of motion of the ball, t = 1.5 s
  • Let the height of the rail = h

<h3>Maximum height of fall;</h3>
  • The maximum height through which the ball was dropped from is calculated by applying second equation of motion;

h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = \frac{1}{2} (9.8) (1.5)^2\\\\h = 11.025 \ m

Thus, the height of the rail on top of the press box where the ball was dropped from is 11.025 m.

Learn more about height of projectiles here: brainly.com/question/10008919

3 0
2 years ago
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