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ira [324]
2 years ago
11

The_____ form acidic compounds with hydrogen.

Physics
2 answers:
dsp732 years ago
7 0
Chlorine forms hydrochloric acid when reacted with hydrogen
PSYCHO15rus [73]2 years ago
6 0

Answer:

chlorine form

Explanation:

hope it helps

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One ounce of a well-known breakfast cereal contains 103 Calories (1 food Calorie = 4186 J). If 1.6% of this energy could be conv
faust18 [17]

Answer:

the heaviest barbell that could be lifted  is 390.6kg

Explanation:

Hello!

To solve this question you must follow the following steps

1. Find the amount of energy that can transform the body into motion, this is achieved by multiplying the breakfast consumed by the percentage of energy conversion.

W=(103Calories)(0.016)\frac{4186J}{1calorie} =6898.5J

2. We use the equation that defines the work done by a body that has weight when it is lifted, this is defined by the product of mass by gravity by height.

W=mgh

where

W=work=6898.5J

m=mass

g=gravity=9.81m/s^2

h=height=1.8m

now we solve for mass, and use the values.

m=\frac{W}{hg} =\frac{6898.5}{(1.8)(9.81)} =390.6kg

the heaviest barbell that could be lifted  is 390.6kg

5 0
2 years ago
A golf club exerts an average horizontal force of 1000 n on a 0.045 -kg golf ball that is initially at rest on the tee. the club
OlgaM077 [116]
The impulse (the variation of momentum of the ball) is related to the force applied by
\Delta p = F \Delta t
where \Delta p is the variation of momentum, F is the intensity of the force and \Delta t is the time of application of the force. 
Using F=1000 N and \Delta t = 1.8 ms=1.8 \cdot 10^{-3}s, we can find the variation of momentum:
\Delta p = (1000 N)(1.8 \cdot 10^{-3} s)=1.8 kg m/s

This \Delta p can be rewritten as
\Delta p = p_f - p_i = mv_f - mv_i
where p_f and p_i are the final and initial momentum. But the ball is initially at rest, so the initial momentum is zero, and
\Delta p = mv_f
from which we find the final velocity of the ball:
v_f =  \frac{\Delta p }{m}= \frac{1.8 kg m/s}{0.045 kg}=  40 m/s
8 0
2 years ago
A ball of mass 0.2 kg is dropped from a height of 10 m. How much mechanical energy does it have right before it hits the ground?
Bad White [126]
0.2 kg * 9.81 m/s^2* 10= 19.62 or B
7 0
3 years ago
Read 2 more answers
A particle of unit mass moves in a potential V(x)= ax^2+b/x^2 . Where a and b are constnts. Calcuate the angular frequency of sm
Sholpan [36]

Answer:

Explanation:

Given

Potential Energy is given by

U(x)=ax^2+\frac{b}{x^2}

And Force is given by

F=-\frac{\mathrm{d} U}{\mathrm{d} x}

Particle will be at equilibrium when Potential Energy is either minimum or maximum

F=-\left ( 2ax-\frac{2b}{x^3}\right )

i.e.ax=\frac{b}{x^3}

x_0=(\frac{b}{a})^{0.25}

So angular Frequency of small oscillation is given by

\omega =\sqrt{\frac{U''(x)}{m}}

for m=1

we get    \omega =\sqrt{\frac{U''(x_0)}{1}}

U''(x_0)=2a+6a= 8a

\omega =\sqrt{8a}

4 0
2 years ago
Which of the following are capital cities in the Caribbean? Lima La Habana San Juan San Jos Guinea Ecuatorial
mars1129 [50]

Caribbean:
Habana ... Cuba
San Juan ... Puerto Rico
San Jose ... Costa Rica

Other:
Lima ... capital of Peru in South America
Equatorial Guinea ... country in Africa

5 0
2 years ago
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