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Grace [21]
3 years ago
6

Four distinguishable particles move freely in a room divided into octants (there are no actual partitions). Let the basic states

be given by specifying the octant in which each particle is located. How many basic states are there?
Physics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

Explanation:

Since the door that leads to the room is opened, this gives room for particles to move into the next identical room and divided into octants. Now the amount of space that can be occupied becomes double, the number of basic states has increased by 404916

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Explanation:

If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

Where:

V_{f}=0 Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)

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Isolating  V_{o} from (1):

V_{o}=\sqrt{-2ad} (2)

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