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beks73 [17]
3 years ago
7

Which could be the dimensions of a rectangular prier whose surface area is less than 180 square feet? Select two options,

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

8 feet by 3 feet by 7 feet

7 feet by 6 feet by 4 feet

Step-by-step explanation:

8 × 3 × 7 = 168

7 × 6 × 4 = 168

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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Y = x^3 + 5x^2 + 3x x= -3
dexar [7]

Answer:

9

Step-by-step explanation:

-3^3 +5*(3)^2 +3*-3

-27+5*9+(-9)

-27+45-9

=9

8 0
3 years ago
Read 2 more answers
Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
Two numbers are in the ratio 2:3 and their sum id 45 then find both number​
Goryan [66]

Answer:

Step-by-step explanation:

Let the two numbers be 2x and 3x.

According to the question,

2x+3x=45

5x=45

x=45/5

x=9

so th required numbers are 18 and 27 as

2x=2*9=18

3x=3*9=27

8 0
3 years ago
Read 2 more answers
Mindy saves more than $12.70
stich3 [128]

Answer:

$63.00 is the closet answer.

Step-by-step explanation:

12.70 x 5

      12.7

×     5

------------------

       13  

       63.5

Therefore, 12.7×5=63.5.

$63.5

5 0
3 years ago
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