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Vladimir [108]
3 years ago
12

Which graph represents the function f (x) = StartFraction 2 x minus 1 Over x minus 1 EndFraction

Mathematics
1 answer:
maw [93]3 years ago
4 0

Answer:

A on edge 2020

Step-by-step explanation:

from that one guys comment^^  

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Insert each of the following numbers between two consecutive multiples of 5: 13 37 48 61 93
DedPeter [7]
10 (13) 15
35 (37) 40
45 (48) 50
60 (61) 65
90 (93) 95
7 0
2 years ago
Which ratio correctly compares 8 pounds to 64, ounces when the lengths are written using the same units? Note: 16 ounces = 1 pou
oksano4ka [1.4K]
Answer: C

64 divided by 8 = 8
8 divided by 8= 1

1:8
7 0
3 years ago
Read 2 more answers
The useful life of a radial tire is normally distributed with a mean of 30,000 miles and a standard deviation of 5000 miles. The
otez555 [7]

Answer:

  empirical rule: 81.5%

  table or calculator: 81.9%

Step-by-step explanation:

The lower limit of the life range of interest has a z-score of ...

  z = (x -μ)/σ = (20,000 -30,000)/5,000 = -2

The upper limit has a z-score of ...

  z = (35,000 -30,000)/5,000 = 1

<u>Empirical rule solution</u>

The empirical rule tells you that 95% of the distribution lies within 2 standard deviations of the mean, so (100% -95%)/2 = 2.5% lie below z = -2. It also tells you 68% lie within 1 standard deviation of the mean, so (100% -68%)/2 = 16% lie above z = 1.

The fraction that lies within -2 to 1 standard deviations of the means is thus ...

  (100% -2.5% -16%) = 81.5%

The probability the tire has a life in the desired range is about 81.5%.

__

<u>Calculator solution</u>

A probability calculator for the Normal distribution tells you that ...

  P(-2 < z < 1) ≈ 0.8185946

The probability the tire has a life in the desired range is about 81.9%.

6 0
2 years ago
Can you arrange 25 small squares to make a larger square? Can you arrange
mote1985 [20]
Yes for the first one and I think yes for 2nd
8 0
2 years ago
The fan below has been stretched open as far as it will go to form a semi-circle.
Komok [63]

Answer:

Area of each sector=12.6cm^2

Step-by-step explanation:

We are given that

Length of each wooden od that connects the center of the fan to its edge ,r=12 cm

Total number of sectors=18

We have to find the approximate area of each sector.

Area of semi-circle=\frac{1}{2}\pi r^2

Using the formula

Area of fan=\frac{1}{2}\pi (12)^2=72 \pi cm^2

Area of each sector=\frac{area\;of\;fan}{Total\;number\;of\;sectors}

Area of each sector=\frac{72\pi}{18}=\frac{72\times 3.14}{18} cm^2

Where \pi=3.14

Area of each sector=12.56cm^2\approx 12.6 cm^2

5 0
3 years ago
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