Answer:
Yes
Step-by-step explanation:
First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.
It has mean μ= np = 30×0.56=16.8
standard deviation s = √npq
sqrt(30×0.56×(1-0.56)) = 2.71
So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.
Answer:
use the cymath calculator
Step-by-step explanation:
Answer:
2x+4
Step-by-step explanation:
Given that a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11
By definition of arithmetic mean,
we have 
Let us calculate sum of a,b,c in terms of x
a+b+c = 
Average = sum/3 = 
That is correct. how did you come up with that.