Answer:
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Explanation:
The free energy of the reaction is given by :
where,
= standard Gibbs free energy
R = Gas constant = 
T = temperature in Kelvins
K = equilibrium constant
We have :
1 kJ = 1000 J
T = 37.0 C = 37 +273.15 K = 310.15 K
Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9
![\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]](https://tex.z-dn.net/?f=%5CDelta%20G%3D-16%2C700%20J%2Fmol%2B8.314J%2FK%20mol%5Ctimes%20310.15%20K%20%5Cln%5B21.9%5D)
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Answer:
The answer to your question is π = 12.47 atm
Explanation:
Data
mass of Magnesium citrate = 25.5 g
volume of solution = 244 ml
temperature = 37°C
molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g
Osmotic pressure = π = ?
Process
1.- Calculate the moles of magnesium citrate
214 grams ----------------- 1 mol
25.5 grams --------------- x
x = (25.5 x 1)/214
x = 0.119
2.- Calculate molarity
Molarity = moles/volume
Molarity = 0.119/0.244
Molarity = 0.49
3.- Calculate osmotic pressure
π = MRT
π = (0.49)(0.0821)(37 + 273)
π = (0.49)(0.0821)(310)
π = 12.47 atm
CO+2 H2=CH3OH
2.85 mol Co x (2mol H2/1 mol Co)=5.70 mol just concert to grams
5.70 mol H2 x (2 g H2/1 mol H2) =11.40 grams of H2
Answer:
Half life = 79.67 sec
Explanation:
Given that:
k = 
The expression for half life is shown below as:-
Where, k is rate constant
So,
Half life = 79.67 sec
Answer:
Both molarity and formality express concentration as moles of solute per liter of solution. Formality is a substance's total concentration in solution without regard to its specific chemical form. ... The formality of a solution is defined as the number of formula mass of any solute dissolved in 1 litre of solution.
