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3 years ago

Question 1 (1 point) ROOTS--What is NOT a root function in plants?

Chemistry

1 answer:

Jlenok [28]3 years ago

3 0

Answer:

deez nuets

Explanation:

bf gm Jr rj if dl if did fll j fll kd golf du is no u to

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Which statement is true about the elements in the periodic table?

aleksandr82 [10.1K]

The correct answer is elements in family 7 have similar properties because elements in the same group or family have the same number of valence electrons.

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3 years ago

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How many Oxygen Atoms & Lithium Atoms Are in 4Li2O? Please Help!

Advocard [28]

Answer:

8 lithium atoms and 4 oxygen atoms

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3 years ago

Trisha and her lab partner were conducting a variety of experiments to produce gases: hydrogen, oxygen, and carbon dioxide. In o

GaryK [48]

Given:

Volume of HCl = 150 ml

Molarity of HCl = 0.10 M

To determine:

The # moles of HCl

Explanation:

The molarity of a solution is the number of moles of a solute dissolved in a given volume

In this case:

Molarity of HCl = moles of HCl/volume of the solution

moles of HCl = Molarity * volume = 0.10 moles.L-1 * 0.150 L = 0.015 moles

Ans: A)

Moles of HCl is 0.015

7 0

4 years ago

How many molecules is 2.03 moles of Al(SO4)3?

Elena L [17]

2.03 molecules times 6.022E23 = 1.22E24

4 0

3 years ago

Which statement below correctly describes the relationship between Q and K for both reactions? Are these reactions spontaneous a

nikklg [1K]

Answer:

Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Explanation:

Hello,

In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:

$A->B;\Delta _rG^o=-13 kJ/mol$

$C ->D ;\Delta _rG^o=3.5 kJ/mol$

The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.

For each case, the reaction quotient is:

$Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167$

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

$K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249$

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Best regards.

6 0

3 years ago