The graph below shows how the temperature and volume of a gas vary when

This compound, an eight-carbon alkane, serves as the 100 octane standard for gasoline. It has five methyl groups, one quaternary

Reika [66]

Answer:

2,2,4-Trimethyl-pentane

Explanation:

Structural characteristics of the compound is as follows:

Has five methyl group
Has one quaternary carbon
No. double bond
Gives four monochloro substitution products

Compound must have straight chain of 5 carbons.

Three methyl substituents are attached to 2 and 4 carbons.

Therefore, IUPAC name of the compound will be 2,2,4-Trimethyl-pentane.

5 0

3 years ago

16 meters per hour to miles per sec

ss7ja [257]

Answer:

2.76 (full answer) 2.7617e-6

Explanation:

6 0

2 years ago

25.0 mL of nitrous acid (HNO2) is titrated with a 1.235 M solution of KOH. The equivalence point (stoichiometric point) is obser

tatuchka [14]

Answer:

0.456 M

Explanation:

Step 1: Write the balanced neutralization equation

HNO₂ + KOH ⇒ KNO₂ + H₂O

Step 2: Calculate the reacting moles of KOH

9.26 mL of 1.235 M KOH react.

0.00926 L × 1.235 mol/L = 0.0114 mol

Step 3: Calculate the reacting moles of HNO₂

The molar ratio of HNO₂ to KOH is 1:1. The reacting moles of HNO₂ are 1/1 × 0.0114 mol = 0.0114 mol.

Step 4: Calculate the initial concentration of HNO₂

0.0114 moles of HNO₂ are in 25.0 mL of solution.

[HNO₂] = 0.0114 mol / 0.0250 L = 0.456 M

3 0

3 years ago

Which is not true about the upper paleolithic period?.

jok3333 [9.3K]

Answer:The Upper Paleolithic period started about 40,000 years BC and ended about 10,000 years BC. So it took place between 40,000 and 10,000 BC. After that started the Mesolithic Era ( 10,000 to 4,000 BC ). Stone tools in the Upper Paleolithic period were primarly blade-based technology. Also this period is well known for the cave art and paintings of animals. Answer: C ) The period took place between 40,000 and 4,000 BC ( not true ).

Explanation:

5 0

2 years ago

in carbon tetrachloride proceeds as follows: 2N2O5→4NO2+O2. The rate law is first order in N2O5. At 64 ∘C the rate constant is 4

Nesterboy [21]

Answer:

Part A

$rate= 4.82*10^{-3}s^{-1} * [N2O5]$

Part B

$rate= 1.35*10^{-4}Ms^{-1}$

Explanation:

Part A

<em>The rate law is the equation that relates the rate of the reaction, the kinetic constant and the concentration of the reactant or reactants.</em>

For the given chemical reaction we can write a general expression for the rate law as follows:

$rate= k * [N2O5]^{x}$

where k is the rate constant and x is the order of the reaction with respect of N2O5 concentration. Particularly, <em>a first order reaction kinetics indicate that the rate of the reaction is directly proportional to the concentration of only one reactant</em>. Then x must be 1.

Replacing the value of the rate constant given in the text we can arrive to the following expression for the rate law:

$rate= 4.82*10^{-3}s^{-1} * [N2O5]$

Part B

Replacing the value of the concentration of N2O5 given, we can get the rate of reaction:

$rate= 4.82*10^{-3}s^{-1} *2.80*10^{-2}M$

$rate= 1.35*10^{-4}Ms^{-1}$

8 0

3 years ago