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boyakko [2]
3 years ago
14

In the reaction 2H2O (l) + 2Cl– (aq) → H2 (g) + Cl2 (g) + 2OH– (aq), which substance is oxidized?

Chemistry
1 answer:
pashok25 [27]3 years ago
3 0

F. None of the above [Cl^(-) is oxidized]

<em>No Cl atoms are available</em> to be oxidized, only Cl^(-)ions

2Cl^(-) → Cl_2 + 2e^(-)

The substance that <em>loses electrons</em> is oxidized.

Remember <em>OIL</em> RIG (<em>O</em>xidation<em> I</em>s <em>L</em>oss of electrons) and

<em>LEO</em> the lion says GER (<em>L</em>oss of Electrons is <em>O</em>xidation).

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4. Find the pH at each of the following points in the titration of 25 mL of 0.3 M HF with 0.3 M NaOH. The Ka value is 6.6x10-4 a
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Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

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Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

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x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

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However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

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