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boyakko [2]
3 years ago
14

In the reaction 2H2O (l) + 2Cl– (aq) → H2 (g) + Cl2 (g) + 2OH– (aq), which substance is oxidized?

Chemistry
1 answer:
pashok25 [27]3 years ago
3 0

F. None of the above [Cl^(-) is oxidized]

<em>No Cl atoms are available</em> to be oxidized, only Cl^(-)ions

2Cl^(-) → Cl_2 + 2e^(-)

The substance that <em>loses electrons</em> is oxidized.

Remember <em>OIL</em> RIG (<em>O</em>xidation<em> I</em>s <em>L</em>oss of electrons) and

<em>LEO</em> the lion says GER (<em>L</em>oss of Electrons is <em>O</em>xidation).

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In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blu
Kaylis [27]

Answer:

Dipole-dipole interactions

Step-by-step explanation:

Each molecule consists of <em>two different elements</em>.

Thus, each molecule has permanent <em>bond dipoles</em>.

The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.

"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.

There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.

4 0
3 years ago
How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?
jolli1 [7]

Answer:

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

where R is the molar constant of the gases and n the number of moles.

In this case you know:

  • P= 7.5 atm
  • V= 2.3 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 24 °C= 297 °K (being 0°C=273°K)

Replacing:

7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K

Solving:

n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}

n=0.708 moles

Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

mass=\frac{0.708 moles*32 grams}{1mole}

mass= 22.656 grams

<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>

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Explanation:

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A scientist triples the temperature of a gas at constant pressure. By what factor does the gas’s volume change?
laila [671]
Hey there,

A scientist triples the temperature of a gas at constant pressure. By what factor does the gas’s volume change?

I believe that  when the scientist triples the temperature of the gas at a certain and constant pressure, the factor of the gas volume would change most likely with the double amount of pressure that the scientist put in the first place.

~Jurgen
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What is the product of radioactive decay 4/2he called?
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