All categories

3 years ago

The diameter of a circle is __________.

Mathematics

2 answers:

Orlov [11]3 years ago

6 0

Answer:

The answer is C

Step-by-step explanation:

Tamiku [17]3 years ago

3 0

Answer: The answer is C

You might be interested in

Someone please help!! I’ll give brainliest!

snow_lady [41]

Answer:

1766.3

Step-by-step explanation:

V=4 /3πr^3

= 4/3(3.14)(7.5)^3

= 4/3(3.14)(421.88)

= 4/3(1324.69)

= 1766.25

= 1766.3

I hope this is right!

3 0

3 years ago

This one is about swings so yeaaa

Tpy6a [65]

Answer:

Ratio is 2:1

Step-by-step explanation:

8 0

3 years ago

Nigel tried to solve an equation step by step

kaheart [24]

Answer:

Step-by-step explanation:

8 0

3 years ago

Each inhabitant of a remote village always tells the truth or always lies. A villager willgive only a ""Yes"" or ""No"" response

pshichka [43]

Step-by-step explanation:

This is actually a very old riddle, but it is two guards and two doors life death .

So let's apply the same logic to this one.

You only meet one villager and you don't know if he is one of the ones who only tells the truth or always lies, to answer this riddle, the question is actually to an hypothetical third party, another villager, not present, this is a little convoluted so bear with me:

(Pointing to one of the roads): If I asked another villager if this road would lead me to the ruins, would he be correct?

If the villager is a truth one, the true-villager, would tell you that the liar-villager would say no (thus leading you to the jungle).

Let's analyze this one, so the villager always tells the truth, and you happen to be pointing to the right direction (ruins), he is answering, that if you would ask another villager whether that is the correct road, that villager would say yes, since you are pointing at the right direction, a liar would tell you no, because the liar would point you to the other road as the correct (jungle), so the true-villager will say no

If you happen to be pointing to the wrong direction (jungle), he is answering, that if you would ask another villager whether that is the correct road, that villager would say yes, since you are pointing at the wrong direction, the truth-villager would tell you no, because the liar would point you to the wrong road as the correct (jungle), so the villager will say no

Therefore, no matter what villager you run into, the question will always lead you to the jungle, and therefore you pick the other road.

4 0

4 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago