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2 years ago

3v=4.8 what is v anwser

Mathematics

2 answers:

fredd [130]2 years ago

5 0

Answer:

1.6=v

Step-by-step explanation:

lapo4ka [179]2 years ago

5 0

Answer:

v=1.6

Step-by-step explanation:

divide both sides by 3

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Joan Messineo borrowed $47,000 at a 5% annual rate of interest to be repaid over 3 years. The loan is amortized into three eq

tester [92]

Answer:

a) The value of the Annual Payment is A=$17,258.80

b) Is the picture in the attachment file

c) As you can see it in the picture with each payment, balance comes down, due it is the interest base, Interest portion comes down too.

Step-by-step explanation:

a) First of all, we are going to list the Knowns: $VP=47000$ , $i=5$ % and $n=3$ , Then we can use $A=\frac{VP}{\frac{1-(1+i)^{-n} }{i} } =\frac{47000}{\frac{1-(1+0.05)^{-3} }{0.03} }=17258.80$ . So this is the value of the Annual Payment

6 0

3 years ago

Miriam is setting up a fishing game in a kiddie pool for her niece's birthday party. The pool has a circular base with a diamete

AURORKA [14]

Answer:

4.7 feet³ of water

Step-by-step explanation:

Diameter of 4 feet

Radius = 2 feet

Height = 0.75 feet

Formula for Volume = 2· $\pi$ ·radius·height

But she only wants to fill half, so divide by 2, cancels the 2 in the formula for volume, giving us: $\pi$ ·radius·height

$\pi$ ·2·0.75 = 4.71 feet³

7 0

3 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

3 years ago

Emma is carpeting 2 perfectly square rooms.

ivolga24 [154]

She's wrong. If you have two squares, $S_1$ with side $s_1$ and $S_2$ with side $s_2$ , it's not true that the sum of their areas is equivalent to the area of a square $S_3$ with side $s_3=s_1+s_2$ .