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4 years ago

Metallic bonding, involving the electron sea model, occurs in ______.

1 answer:

4 0

B, only metals. Metallic bonding always occurs between metals of the same element and involves “a sea of mobile electrons”

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Will a tower of straws hold tennis balls

coldgirl [10]

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3 years ago

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Give the name and formula of the compound formed when a Mn2+ cation combines with a (PO4)3- anion

alex41 [277]

Sodium mn2 and po4 makes sodium

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3 years ago

3- Um tipo de nutriente complexo presente

umka21 [38]

Answer:

The human body when metabolizing meat, milk or eggs, being high in protein, manufactures uric acid as a metabolite, and releases more urea in the urine.

Uric acid generates an increased retention of liquid or water, that is why people who ingest excessively meat suffer from GOTA disease.

Gout disease is systemic and life-threatening puffiness.

Furthermore uric acid is an organic compound of carbon, nitrogen, oxygen and hydrogen. Its chemical formula is C5H4N4O3. It is found in urine in small amounts.

And urea is defined as a renal parameter from the quantitative point of view; It is a colorless, crystalline chemical compound of formula CO (NH2) 2. It is found abundantly in urine and faeces.

Explanation:

To have an accurate idea of the function of the kidneys, it is sufficient to carry out a simple blood test with determination of Urea and creatinine and an analysis of a urine sample in which the presence of cells (red blood cells and leukocytes) is assessed. and / or proteins (albumin). Today these 2 types of analysis are part of the routine of any analytical study.

4 0

3 years ago

What is the frequency and energy per quantum (in Joules) of :

viktelen [127]

(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;

(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.

<h3>Explanation</h3>

What's the similarity between a gamma ray and a microwave?

Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at $3.00 \times 10^{8}\;\text{m}\cdot\text{s}^{-1}$ in vacuum.

$f = \dfrac{c}{\lambda}$

where

f is the frequency of the electromagnetic radiation,
c is the speed of light, and
$\lambda$ is the wavelength of the radiation.

(a)

Convert all units to standard ones.

$\lambda = 0.600\;\text{pm} = 0.600 \times 10^{-12} \;\text{m}$ .

The unit of $f$ shall also be standard.

$f = \dfrac{c}{\lambda} = \dfrac{3.00\times 10^{8}\;\text{m}\cdot\text{s}^{-1}}{0.600\times 10^{12}\;\text{m}} = 5.00 \times 10^{20}\;\text{s}^{-1}= 5.00\times 10^{20}\;\text{Hz}$ .

For each particle,

$E = h\cdot f$ ,

where

$E$ is the energy of the particle,
$h$ is the planck's constant where $h = 6.63\times 10^{-34}\;\text{J}\cdot\text{s}^{-1}$ , and
$f$ is the frequency of the particle.

$E = h \cdot f = 6.63\times10^{-34}\;\text{J}\cdot\text{s}\times 5.00\times 10^{20}\;\text{s}^{-1} = 3.32\times10^{-13}\;\text{J}$ .

(b)

Try the steps in (a) for this beam of microwave with

$\lambda = 2.50 \;\text{cm} = 2.50\times 10^{-2}\;\text{m}$ .

Expect the following results:

$f = 1.20\times 10^{10}\;\text{Hz}$ , and
$E = 7.96\times 10^{-24}\;\text{J}$ .

4 0

3 years ago

How many grams of Br are in 335g of CaBr2

ASHA 777 [7]

The answer is 267.93 g

Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g

7 0

3 years ago