The question was not well arranged above. It has been arranged in the answer below.
Question:
Leon made a study chart about human-induced changes to the environment.
Environmental Changes Caused by Humans
X Y
Results from introducing harmful substances into the environment
Example: oil spill
Results from natural areas being cleared and replaced by human development
Example: deforestation
Which headings best complete the chart?
X: Habitat Destruction
Y: Pollution
X: Long-Term Changes
Y: Short-Term Changes
X: Short-Term Changes
Y: Long-Term Changes
X: Pollution
Y: Habitat Destruction
Answer:
X: Pollution
Y: Habitat Destruction
Explanation:
From the above question, Leon gave us two variables, X and Y.
The human induced changes were divided into two.
1. Results from introducing harmful substances into the environment
Introducing harmful substances into the environment is also called pollution. And we can represent this as X which is the first variable.
2. Results from natural areas being cleared and replaced by human development.
This description given in number two above whereby land areas are been cleared and replaced by human development has a negative effects on the environment because the vegetation which includes the trees are been cut down and living organisms(animals) will go extinct gradually. This act affect the balance of the ecosystem and it can be referred to as the destruction of the habitat of living organisms
Therefore, the correct headings best complete the chart is :
X: Pollution
Y: Habitat Destruction
To determine the pH of a solution which has 0.195 M hc2h3o2 and 0.125 M kc2h3o2, we use the ICE table and the acid dissociation constant of hc2h3o2 <span>to determine the concentration of the hydrogen ion present at equilibrium. We do as follows:
HC2H3OO = H+ + </span>C2H3OO-
KC2H3OO = K+ + C2H3OO-
Therefore, the only source of hydrogen ion would be the acid. We use the ICE table,
HC2H3OO H+ C2H3OO-
I 0.195 0 0.125
C -x +x +x
------------------------------------------------------------------
E 0.195-x x 0.125 + x
Ka = <span>1.8*10^-5 = (0.125 + x) (x) / 0.195 -x
x = 2.81x10^-5 M = [H+]
pH = - log [H+]
pH = -log 2.81x10^-5
pH = 4.55
Therefore, the pH of the resulting solution would be 4.55.</span>
<span>Alkyl is a rare compound, and also very confusing.
I'm assuming you meant "propane"...
</span>
<span><span><span>C3H<span>8 = Propane
</span></span>CnH2n+1--
X</span> << Alkyl Halide
X = Cl
Simply set a chemical reaction :
</span>
<span>C3H<span>8 → </span></span><span>CnH2n+1--
X </span>
