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kap26 [50]
3 years ago
11

If, for each mouse, the probability of turning left is 0.5 and the probability of turning right is 0.5, what is the probability

that only one of the three mice will turn left?
Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

Answer:

.125

Step-by-step explanation:

(.5)^2(.5)^1= .125

Where (.5)^2 is the probability two mice turn left multiplied by (.5) that one of them turns right.        

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Fred flips a coin, spins the spinner, and rolls a standard number cube. Find the probability that the coin will show tails, the
Inessa05 [86]

Answer:

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is \frac{4}{3}  

Step-by-step explanation:

Given : Fred flips a coin, spins the spinner, and rolls a standard number cube.

To find : The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three ?

Solution :

First we find probability one by one,

1) Flips a coin - Head, Tail

Total number of outcome = 2

Favorable outcome (getting a tail) = 1

Probability that the coin will show tails is P(T)=\frac{1}{2}

2) Spins the spinner - yellow, green, blue

Total number of outcome = 3

Favorable outcome (land on yellow or green) = 2

Probability that the spinner will land on yellow or green P(S)=\frac{2}{3}

3) Rolls a standard number cube - 1,2,3,4,5,6

Total number of outcome = 6

Favorable outcome (show a three) = 1

Probability that the cube will show a three P(C)=\frac{1}{6}

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is

P=P(T)+P(S)+P(C)

P=\frac{1}{2}+\frac{2}{3}+\frac{1}{6}

P=\frac{3+4+1}{6}

P=\frac{8}{6}

P=\frac{4}{3}

Therefore, The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is \frac{4}{3}

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See, pls, the attached picture, the area determined by the conditions marked by yellow lines.

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If the greatest number of pools installed is 18, then the fewest pools installed Is 6.
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