Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
A
Step-by-step explanation:
The Pythagorean theorem can be used for this.
.. (tip distance)² = (shadow length)² + (tree height)²
.. tree height = √((tip distance)² -(shadow length)²)
.. tree height = √((60 ft)² -(40 ft)²) = √(2000 ft²)
.. tree height ≈ 44.72 ft
Answer:
true im not sure tho but trust me
Step-by-step explanation:
