Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)
Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141
(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71
(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000
</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x
taking "ln" on both sides:
ln(4.797) = ln(1.19)^x
ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)
Let x represent the number of shirts. Let y represent the number of pens.
If shirts are on sale for $11.99 each, then x shirts cost $11.99x.
If pants are on sale for $12.99 each, then y pants cost $12.99y.
The total cost is $(11.99x+12.99y).
Sarah can spend up to $65. Then an inequality that represents this situation is
11.99x+12.99y≤65 (this inequality holds when Sarah can spend $65 too)
or
11.99x+12.99y<65 (this inequality holds when Sarah can spend less than $65).
Solve for x. so first u would subtract 25 from 25 and 298. 25 will be crossed out so now u are left with 13x<273. to solve that, divide 13 on both sides. 13 would be crossed or so now u are left with x<13. that means x can equal anything less than 13. idk about the rest, i think u can do it. :)
The subway car passes through 48 stations in 2hours
It is given that a subway car passes 4 stations every 10 mins.
Subway car is being referred to the metro system of New York city
It is known to us that an hour has 60 mins
We are given that subway car passes 4 stations every 10 mins
Therefore number of stations passed by subway car in 1 hour
= 60/10 x 4 = 24 stations
We are required to find the number of stations crossed by subway car in 2 hours
Therefore, number of stations crossed by subway car in 2 hours= 24 x 2
= 48 stations
Therefore, the subway car passes 48 stations in 2 hours
For further reference:
brainly.com/question/5451948?referrer=searchResults
#SPJ9
