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OLga [1]
3 years ago
6

Please help!!! (Look at photo)

Mathematics
1 answer:
Alexxx [7]3 years ago
4 0

Answer:

330=40x+50

Step-by-step explanation:

then you would -50 from both sides

280=40x

then you would divide both sides by 40 to isolate x

7=x

so that means it would take 7 weeks

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I need help on the first 2
Aleksandr [31]
With what? Questions?
6 0
3 years ago
What is the mode: 18,21,22,18,19
Evgesh-ka [11]

Answer:

18

Step-by-step explanation:

Mode =  modal class (Recurring)
The number/value that appears the most which in this case is 18 because it can be seen twice.

6 0
2 years ago
What is the volume of the composite figure?
Sladkaya [172]

Answer:

748 in^3.

Step-by-step explanation:

This consists of a triangular prism and a  rectangular cuboid .

Volume of the prism =  .1/2 * 8 *11 * 17 = 748 in^3

Volume of the cuboid =  5*8*17 = 680 in^3

Therefore the volume of the whole figure

= 680 + 748 =  1428 in^3.

6 0
3 years ago
Evaluate. 43⋅(10025)−50
Roman55 [17]
The dot means to multiply
so 43 x 10025 -50
since BEDMAS is applied,
we would do the multiplication first
43 x 10025 = 431075 
and <span>431075 - 50 is 431025
FINAL ANSWER: 431025</span>
8 0
3 years ago
Read 2 more answers
Please answer ASAP. The question is down below.
Butoxors [25]

Answer:  1) c     2) d

<u>Step-by-step explanation:</u>

Use Pythagorean Theorem to find the hypotenuse (r):  x² + y² = r²

Given: x = 2, y = 6

                2² + 6² = r²

                4 + 36 = r²

                      40 = r²

                      \sqrt{40}=r

\sin \theta=\dfrac{y}{r}\quad =\large\boxed{\dfrac{6}{\sqrt{40}}}\quad \rightarrow \dfrac{6}{2\sqrt{10}}\quad \rightarrow \dfrac{3}{\sqrt{10}}

*******************************************************************************************

\sin \theta = \dfrac{opposite(y)}{hypotenuse(r)}\quad =\dfrac{12}{20}\quad \rightarrow \dfrac{3}{5}\quad \rightarrow \large\boxed{0.6}\\\\\\\cos \theta = \dfrac{adjacent(x)}{hypotenuse(r)}\quad =\dfrac{16}{20}\quad \rightarrow \dfrac{4}{5}\quad \rightarrow \large\boxed{0.8}

5 0
3 years ago
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