Question

The graph of which function passes through the point (0,2/pi)?

Answer 1

Answer:

$y=sin^{-1}x$

Step-by-step explanation:

Given: A point is $(0,2\pi)$

To find: function whose graph passes through the given point

Solution:

A trigonometry explains the relationship between the sides and the angles of the triangle.

The inverse trigonometric functions $sin^{-1}x\,,\,cos^{-1}x\,,\,tan^{-1}x$ help to find the value of an unknown angle of a right triangle when length of two sides are given.

Consider $\sin y=x$

Put $y=2\pi$

$sin 2\pi=0$

So, point $(0,2\pi)$ satisfies the function $y=sin^{-1}x$

Therefore, graph of function $y=sin^{-1}x$ passes through $(0,2\pi)$