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Step2247 [10]
4 years ago
7

If y varies directly as x, and y is 20 when x is 4, whats this relation?

Mathematics
1 answer:
nignag [31]4 years ago
7 0
Y α x

y = kx

20 = k*4

20 = 4k

20/4 = k

5 = k

k = 5

Relation is y = kx ,  that is    y = 5x
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C

Step-by-step explanation:

1/4--1/2=0.75

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7 0
3 years ago
Read 2 more answers
7+6 (mod 5) =<br><br>2+1 (mod 5) =<br><br>20 (mod 11) =<br><br>35 (mod 11) =<br><br>20 (mod 11) =​
ValentinkaMS [17]

Answers:

  • 3
  • 3
  • 9
  • 2
  • 9

======================================

Explanation:

7+6 = 13. Divide this over 5 to get 13/5 = 2 remainder 3. The quotient 2 is something we don't care about. <u>We only worry about the remainder</u>. Therefore 7+6 = 3 (mod 5)

-------------

2+1 = 3 (mod 5) for similar reasoning as above. 3/5 = 0 remainder 3.

-------------

20 = 9 (mod 11) since 20/11 = 1 remainder 9. Imagine you had 20 cookies and 11 friends. Each friend would get 1 whole cookie (quotient) and there could be 9 left over (remainder).

-------------

35/11 = 3 remainder 2

Or you could use repeated subtraction like so to find the remainder

35-11 = 24

24-11 = 13

13-11 = 2

The last result (2) is smaller than 11, so we stop here and this is the remainder.

Therefore, 35 = 2 (mod 11)

--------------

Here's another way to think of it. Consider you have $35 in your pocket. Let's say a store is selling trinkets for $11 each. We can pose these key questions:

  • What is the most number of trinkets you can buy?
  • If you buy that max amount, how much will you have left over?

The answer to the first question is 3 trinkets because 3*11 = 33 dollars is under the budget of $35. The amount left over is 35-33 = 2 dollars which is the remainder. It's not larger than 11, so we cannot buy any more trinkets at this point.

5 0
3 years ago
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