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Sever21 [200]
3 years ago
9

A number, x, rounded to 1 significant figure is 200Write down the error interval for x.​

Mathematics
1 answer:
makkiz [27]3 years ago
4 0

Answer: 150 <= x < 250

Step-by-step explanation:

A number, x, rounded to 1 significant figure is 200

Write down the error interval for x

Rounding x to 1 significant figure means that all subsequent digits after the first is rounded down to zero(0) (if the immediate number after the first is digit 5 or more, it is rounded to 1 and added to the first digit).

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how to solve and write three times a number s plus 4 times a number y is 1 more than 6 times the number s. solve for s
Rasek [7]
3s+4y=1+6s
minus 3s both sides
4y=1+3s
minus 1
4y-1=3s
divide by 3
\frac{4y-1}{3} =s
3 0
3 years ago
The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of
ivanzaharov [21]
<h2>Answer:</h2>

R_2  is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

=>   {R_2} = \frac{R_TR_1}{R_1 - R_T}       ---------------(ii)

From the question,

R_1 = 6Ω

R_T = 2Ω

Substitute these values into equation (ii) as follows;

=> {R_2} = \frac{2*6}{6 - 2}

{R_2} = \frac{12}{4}

R_2 = 3Ω

Therefore, the value of R_2 = 3 ohms or R_2 = 3Ω

3 0
3 years ago
-x+ 2y = 10<br> -3x+By = 11
adoni [48]

Answer:

change the equation into one variable.

2 y equals 10 + x

y equals 5 + x by 2

now put that into the second equation

-3x + b parentheses 5 + x / 2 equals 11

-3x+b(5+ x/2)

-3x + b5 + bx/2 = 11

8 0
3 years ago
Read 2 more answers
What is the solution to the expression 12÷4+(1/3)²⋅9⋅3 ?
krok68 [10]

Answer:

6

Step-by-step explanation:

STEP

1

:

           1

Simplify   —

           3

The equation at the end of step

1

:

 12       1

 —— +  (((—)2) • 9) • 3)

 4        3

STEP

2

:

Equation at the end of step

2

:

 12       1

 —— +  ((—— • 9) • 3)

 4       32

STEP

3

:

Canceling Out:

3.1      Canceling out  32 as it appears on both sides of the fraction line

Equation at the end of step

3

:

 12    

 —— +  (1 • 3)

 4    

STEP

4

:

           3

Simplify   —

           1

Equation at the end of step

4

:

 3 +  3

STEP

5

:

Pulling out like terms

5.1      Pull out     3

After pulling out, we are left with :

     3 • ( 1 - (-1) ))

Final result :

 6

5 0
2 years ago
Read 2 more answers
Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin
katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula A=P(1+\frac{r}{n})^{nt}

In this formula A = amount after time t

                        P = principal amount

                        r = rate of interest

                       n = number of times interest gets compounded in a year

                        t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 15000(1+.06)^{1}

= 15000(1.06) = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 20900(1+.06)^{1}

= 20900(1.06)=22154

So the final amount will be $22154.

3 0
3 years ago
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