There are 31 coins of dimes and quarters. If the number of dimes is 5 more than the number of quarters, how many quarters are th
ere? How many are dimes? Hint: let x=dimes and y=quarters. Write your answer in an ordered pair ( , ).
1 answer:
Answer:
<u>13 Quarters and 18 Dimes</u>
Step-by-step explanation:
Let D and Q stand for the numbers of Dimes(D) and Quarters(Q). Give x and y a break, and make it easier to remember which is which.
D + Q = 31
D = Q + 5
Therefore:
D + Q = 31
(Q+5) + Q = 31
2Q + 5 = 31
2Q = 26
<u>Q = 13</u>
<u>Then D = (13+5) or 18</u>
================
Check:
D + Q = 31 ?
18 + 13 = 31 <u>YES</u>
----------------------
D = Q + 5 ?
18 = 13 + 5 <u>YES</u>
You might be interested in
Answer:
Its B
Step-by-step explanation:
5(-11)+4(3)^2 = -19
The answer is -19
Answer:
[1 , +∞)
Step-by-step explanation:

<h2>Answer :</h2>
Let the number be x. Then according to the question,
Step 1 :- Adding 3
=> x + 3
Step 2 :- Multiply the sum by 2
=> 2×(x + 3)
Step 3 :- Subtract 6
=> 2(x +3) - 6
<h3>Thus the expression becomes 2(x +3) - 6. </h3>