The correct statement regarding the function plotted in the graph is:
C) The maximum value of the quadratic function occurs at y = 4.
<h3>What is the rate of change of the linear function?</h3>
When x = 0, y = -7, and when x = -5, y = 8, hence the rate of change(change in y divided by change in x) is given by:
R = [8 - (-7)]/-5 - 0 = 15/-5 = -3
<h3>What is the maximum value of the quadratic function?</h3>
It is concave down, hence it has only a maximum value at y = 4 and not a minimum value, hence option C is correct.
More can be learned about functions at brainly.com/question/25537936
Answer:
A. 
.
Step-by-step explanation:
We have been given an inequality 
. We are asked to solve the given inequality for x.
Using distributive property, we will get:
Subtract 2 from both sides:
Divide both sides by 7:
Therefore, option A is the correct choice.
<span>8x + 8y = -48
-------------------------
Plug in -8 for x
(8) (-8) + 8y = -48
-------------------------------
Simplify
</span><span><span><span>(8) </span><span>(<span>−8</span>) </span></span>+ <span>8y </span></span>= <span>−<span>48
</span></span><span><span>−64 </span>+ <span>8y </span></span>= <span>−<span>48
</span></span><span><span>8y </span>− 64 </span>= <span>−<span>48
</span></span>-----------------------------------------
Add 64 to each side
<span><span><span>8y </span>− 64 </span>+ 64 </span>= <span><span>−48 </span>+ 64
</span><span>8y </span>= <span>16
</span>---------------------------------------------------
Finally, divide each side by 8
8y ÷ 8 = 16 ÷ 8
y = <span>2
</span>----------------------------------------------------------------
y = 2 is your answer
Answer:
x = 4 when y = 12
Step-by-step explanation:
The ratio of y to x is 6:2. If you multiply either one of them, you must do the same to the remaining number. So, when you multiply 6 by 2 to get 12, you must also multiply 2 by 2 to keep the ratio equal and the same. 2x2 = 4, so x=4 when y=12. Hope this helped! Good luck with other math problems :)
The answer is choice D.
Cause it can't be calculate.
