Answer:
1/3 = 0.333333
16/33 = 0.48484848
2/11 = 0.181818
1/12 = 0.0833333
127/999 = 0.127127127
Step-by-step explanation:
divde each fraction
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
What equation will model the situation?
✔ x/3 = 4
How many servings did the original recipe make?
✔ 12
Step-by-step explanation:
Hope this helps!
149 will be rounded to 150 so 150×5= 750