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Sveta_85 [38]
3 years ago
15

The following frequency table shows the number of fish caught by each of Igor's family members. What was the maximum number of f

ish that a family member caught? _____ fish

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

4

Step-by-step explanation:

The values on the left of the table represent the number of fish caught, and the number of the right of the table represents how many family members caught that amount of fish.

Therefore, the first row means that 0 family members caught 0 fish.

The second row means that 3 family members caught 1 fish.

The third row would mean 1 family member caught 2 fish.

The next row would mean 0 family members caught 3 fish.

And the final row would mean 4 family members caught 4 fish.

The question does not ask for the total amount of fish caught; rather is ask for the maximum number of fish that a single family member caught.

Therefore, the maximum amount of fish that a single family member catches is 4. (And 4 family members did so. But individually, the maximum amount of fish one person caught is 4).

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Last Friday temp at $30 over the weekend he received some money for doing his chores he now has $42 write an equation that repre
JulsSmile [24]
30+x=42 I think because it's has to equal 42 and he already has 30
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3 years ago
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What is the solution to the equation 37x = 9x + 4?<br><br> -7<br><br> -1/7<br><br> 1/7<br><br> 7
aivan3 [116]
37x = 9x + 4

37x - 9x = 4

28x = 4


x = 7
3 0
2 years ago
Read 2 more answers
16 more than s is at most −80.
polet [3.4K]

Answer:

s + 16 ≤ −80

Step-by-step explanation:

Analyze each part in the word equation:

"16 more than s"     s increased by 16; s + 16

"is at most"           is equal to or less than; ≤

"−80"               -80

Put the equation back together:

s + 16 ≤ −80

4 0
3 years ago
1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

Now, 

\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
3 0
3 years ago
Jack and Jill start driving from the same location. Jack drives 30 miles south while Jill drives west. If Jack and Jill are 78 m
arsen [322]

Answer:

72 mles

Step-by-step explanation:

For better understanding, I'll make use of an attachment.

From the attachment,

O represents the start point

OB = 30 --- Jack

AB = 78 -- Distance between them

Required

Find OA; Jack's distance

To do this, we make use of Pythagoras theorem

AB^2 = OA^2 + OB^2

This gives:

78^2 = OA^2 + 30^2

6084 = OA^2 + 900

Subtract 900 from both sides

OA^2=  6084 - 900

OA^2=  5184

Take square roots

OA = \sqrt{5184}

OA = 72

<em>Hence, Jill drove 72 miles</em>

5 0
3 years ago
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