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Nikitich [7]
3 years ago
11

Given that an electromagnetic wave is generated by an oscillating electron, how are the frequency of the wave and the oscillatio

n frequency of
the electron related?

A. The frequency of the electromagnetic wave is inversely proportional to the oscillation frequency of the electron.

B. The frequency of the electromagnetic wave is equal to the oscillation frequency of the electron

C. The frequency of the electromagnetic wave has no effect on the oscillation frequency of the electron

D. The frequency of the electromagnetic wave is directly proportional to the oscillation frequency of the electron

E. The frequency of the electromagnetic wave is half of the oscillation frequency of the electron
Chemistry
1 answer:
Alexeev081 [22]3 years ago
3 0

Answer: The frequency of the electromagnetic wave is equal to the oscillation frequency of the electron is the correct option.

Explanation:

Electromagnetic waves are created by oscillating charges. Frequency of waves and oscillation of electron both are the same. Electromagnetic waves are always move perpendicular to the direction in which the wave moves.

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If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th
qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

K_c=4.74\times 10^4

Concentration at equilibrium:

[COBr_2]=1.58\times 10^{-6}M

[Co]=2.78\times 10^{-3}M

[Br_2]=2.51\times 10^{-5}M

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

The expression for reaction quotient will be :

Q=\frac{[CO][Br_2]}{[COBr_2]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}

The given equilibrium constant value is, K_c=4.74\times 10^4

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K_c that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K_c that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the Q that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

3 0
3 years ago
Cu2 -&gt; Cu2+ is it getting oxidized?
KIM [24]

Answer:

Explanation:

Cu²⁺ + 2e⁻  →  Cu   ( copper gets reduced )

Cu  → Cu²⁺ + 2e⁻ (  copper gets oxidized )

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

7 0
3 years ago
Compare<br> Ion and Radical<br> Atom and molecule<br> Organic and inorganic compounds
horrorfan [7]

Answer:

'An ion has a non-zero electric charge. A radical has an atom with unfilled electron shells and so is very reactive, but is electrically neutral.'

'Atoms are single neutral particles. Molecules are neutral particles made of two or more atoms bonded together.'

'The primary difference that lies between these organic compounds and inorganic compounds is that organic compounds always have a carbon atom while most of the inorganic compounds do not contain the carbon atom in them.'

6 0
2 years ago
Read 2 more answers
When an aqueous solution of AgNO3 is electrolyzed, a gas is observed to form at the anode. The gas is
iris [78.8K]

Answer:

Oxygen

Explanation:

First, list out all the ions in the aqueous solution:

Ag+, NO3-

H+, OH-

In the anode, the substance lose electrons to undergo oxidation.

From the 4 ions, only OH- can lose electrons to form water and oxygen,

4OH- --->  O2 + 2H2O + 4e-

While others tend to gain electrons to form new substances instead (they undergo reduction).

Oxygen is the gas produced.

6 0
3 years ago
Which has a higher frequency a neutron or electron
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Neutron or neutral and electran are positive
8 0
3 years ago
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